意外的 T_ELSE [关闭]

Question

我已经创建了一段代码，并且我已经在我的 PHP 代码中“请求一次”了很长一段时间了。它在我的本地 PC 上运行良好，但是当我将它上传到我的服务器时，它会出现以下错误：

Parse error: syntax error, unexpected T_ELSE in /home/makequiz/public_html/nitpicker/func.php on line 47

函数如下：

function howLongAgo($unix_time) {
// This function shows the unix time stamp 
// as number of seconds, minutes, hours, days, months, years ago 


// Get the time difference between time specified and the current unix time 
$time_difference = time () - $unix_time;

$seconds_ago = $time_difference;
$minutes_ago = $time_difference / 60;
$hours_ago = $time_difference / 3600;
$days_ago = $time_difference / 86400;
$months_ago = $time_difference / 2629743;
$years_ago = $time_difference / 31556926;

if ($time_difference < 60) {
    // Seconds Ago 
    return round ( $time_difference ) . ' Seconds Ago';

} else if ( ($time_difference >= 60) && ($time_difference < 3600) ) {

    // Minutes Ago
    if (round ( $time_difference / 60 ) == 1) {
        return round ( $time_difference / 60 ) . " Minute Ago";
    } else {
        return round ( $time_difference / 60 ) . " Minutes Ago";
    }

} else if ($time_difference >= 3600 && $time_difference < 86400) {
    // Hours Ago 
    if (round ( $time_difference / 3600 ) == 1) {
        return round ( $time_difference / 3600 ) . " Hour Ago";
    } else {
        return round ( $time_difference / 3600 ) . " Hours Ago";
    }
} else if ($time_difference >= 86400 && $time_difference < 2629743) {
    // Days Ago 
    if (round ( $time_difference / 86400 ) == 1) {
        return round ( $time_difference / 86400 ) . " Day Ago";
    } else {
        return round ( $time_difference / 86400 ) . " Days Ago";
    }
} else if ($time_difference >= 2629743 && $time_difference < 31556926) {
    // Months Ago 
    if (round ( $time_difference / 2629743 ) == 1) {
        return round ( $time_difference / 2629743 ) . " Month Ago";
    } else {
        return round ( $time_difference / 2629743 ) . " Months Ago";
    }
} else if ($time_difference >= 31556926) {
    // Years Ago 
    if (round ( $time_difference / 31556926 ) == 1) {
        return round ( $time_difference / 31556926 ) . " Year Ago";
    } else {
        return round ( $time_difference / 31556926 ) . " Years Ago";
    }
}
}

这个错误即将出现，即使我的代码中根本没有调用该函数。

任何人都可以看到代码中的任何错误，因为我看不到:(

Answer 1

使用 switch/case 逻辑方案会简单得多。我已经使用 switch/case 重新编码了你在那里的内容，这可能是你学习 switch/case 的一个很好的介绍。在上面的 if 语句之一中，您有一些额外的 ( )。我希望这会有所帮助，朋友：

<?
$unix_time = 6734;
echo howLongAgo($unix_time);

function howLongAgo($time_difference){

// Swtich logic based on the time difference passed to this function, sets the english string and what number the difference needs to be divided by
    switch($time_difference){
         case ($time_difference < 60):
              $string = " second";
              break;
         case ($time_difference >= 60 && $time_difference < 3600):
              $string = " minute";
              $divider = 60;
              break;
         case ($time_difference >= 3600 && $time_difference < 86400):
              $string = " hour";
              $divider = 3600;
              break;
         case ($time_difference >= 86400 && $time_difference < 2629743):
              $string = " day";
              $divider = 86400;
              break;
         case ($time_difference >= 2629743 && $time_difference < 31556926):
              $string = " month";
              $divider = 2629743;
              break;
         case ($time_difference >= 31556926):
              $string = " year";
              $divider = 31556926;
              break;
    }

// If a divider value is set during the switch, use it to get the actual difference
if($divider){$diff = round($time_difference / $divider);}else{$diff = round($time_difference);}
// If the difference does not equal 1, pluralize the final result EG: hours, minutes, seconds
if($diff != 1){$pluralize="s";}
// Concatenate all variables together and return them
$final =  $diff . $string . $pluralize . " ago";
return $final;

}
?>

Answer 2

我认为您的问题可能来自 elseif 和 else if 之间的差异（注意空格）。

来自 PHP website:

注意：请注意，elseif 和 else if 只有在使用大括号时才会被视为完全相同，如上例所示。使用冒号定义 if/elseif 条件时，不能将 else if 分成两个词，否则 PHP 将因解析错误而失败。

Answer 3

您的代码在第 47 行有语法错误（我敢打赌，您在第 46 行缺少半色或括号。

是否调用函数无关紧要，因为 php 解析器会预先分析整个文件。

Answer 4

几件事.. 您是否更改了加载到服务器时包含的文件？ 尝试使用 include 而不是 require？