如何更改响应正文？

Question

这是我将多个属性存储到数据库中的场景。现在，当我获取响应时，我不想要已经存储在 Db 中的确切属性名称。例如，下面是我的代码。在这里，我将字段存储为“ca_xyz”。现在在获取响应时，我只想要“xyz”作为字段名。谁能帮帮我？

const addAddress = async (req, res, next) => {
    try{
        var custid = req.params.id;
         const data = {
             ca_email: req.body.email,
             ca_mobile: req.body.mobile,
             ca_address1: req.body.address1,
             ca_address2: req.body.address2,
             ca_zone_id: req.body.zone_d,
             ca_city: req.body.city,
             ca_local: req.body.local,
             ca_pincode: req.body.pincode,
         }
         let results = await Address.create({data});
         res.send({
            status:'success',
            message:`Successfully added address `
         })
    }
    catch(error){
        console.log(error)
        res.send({
            status:'failed',
            message:"An error occurred"
        })

    }
}

实际上，这就是正在发生的事情。它应该在 dataValues 内循环，但在这里它正在获取“customer_group”对象。

Answer 1

类型安全的方法是手动编写，快速的方法如下，循环遍历对象的条目并删除每个键的前缀。

const data = {
  ca_email: "req.body.email",
  ca_mobile: "req.body.mobile",
  ca_address1: "req.body.address1",
  ca_address2: "req.body.address2",
  ca_zone_id: "req.body.zone_d",
  ca_city: "req.body.city",
  ca_local: "req.body.local",
  ca_pincode: "req.body.pincode",
}

let newData = {};

for (const [key, value] of Object.entries(data)) {
  newData[key.substr("ca_".length)] = value;
}

console.log(newData)