【发布时间】:2019-02-18 16:22:15
【问题描述】:
使用 scala-cat 的 Ior 数据类型我遇到了以下问题:
import cats._
import cats.data._
import cats.implicits._
type Locale = String
type FailureMessage = String
type Failures = NonEmptyList[FailureMessage]
private def listTranslationFiles(): IO[FailureMessage Either Array[File]] = ???
private def analyzeTranslationFiles(fs: Array[File]): Failures Ior Seq[(Locale, File)] = ???
private def readTranslations(): IO[Failures Ior Seq[(Locale, File)]] = for {
files <- listTranslationFiles()
fileIor = if(files.isLeft) (NonEmptyList(files.left.get, Nil): Failures).leftIor
else files.right.get.rightIor
// fileIor: Ior[Failures, Array[File]]
analyzed = fileIor.bimap(identity, analyzeTranslationFiles)
// analyzed: Ior[Failures, Ior[Failures, Seq[(Locale, File)]]]
result = ??? // how do I 'flatten' analyzed here?
} yield result
在我的最后一步中,我需要转换这种类型:
Ior[Failures, Ior[Failures, Seq[(Locale, File)]]]
进入:
Ior[Failures, Seq[(Locale, File)]]
通过某种方式flattening Ior(我想将所有剩余的Ior 累积到顶层Ior 中)。如何做到这一点?
【问题讨论】:
标签: scala functional-programming scala-cats