带有 jerseyServlets 的嵌入式 Jetty 中出现错误“多个 servlet 映射到路径：/*：”

Question

这里似乎有很多问题，但没有一个对我有帮助.... 尝试将单个 Java 类作为起点，使用 Jersey 运行嵌入式 Jetty，以提供网页和 JSON 接口......但是，即使第一步也未能提供多个页面。

这很好用

ServletHolder jerseyServlet = context.addServlet(org.glassfish.jersey.servlet.ServletContainer.class, "/*");
jerseyServlet.setInitOrder(0);      
jerseyServlet.setInitParameter("jersey.config.server.provider.classnames", EntryPoint.class.getCanonicalName());

但添加其他内容失败。如何提供提供不同内容类型的多个页面？ 是在单个 EntryPoint 类中添加内容的唯一解决方案吗？

提前感谢任何提示需要改变它

public class App {
public static void main(String[] args) throws Exception {
    ServletContextHandler context = new ServletContextHandler(ServletContextHandler.SESSIONS);
    context.setContextPath("/");
    Server jettyServer = new Server(8080);
    jettyServer.setHandler(context);

    ServletHolder jerseyServlet = context.addServlet(org.glassfish.jersey.servlet.ServletContainer.class, "/*");
    jerseyServlet.setInitOrder(0);                                                                                  
    jerseyServlet.setInitParameter("jersey.config.server.provider.classnames", EntryPoint.class.getCanonicalName());

    ServletHolder helloWorldServlet = context.addServlet(org.glassfish.jersey.servlet.ServletContainer.class, "/*");
    helloWorldServlet.setInitOrder(1);                                                                                  
    helloWorldServlet.setInitParameter("jersey.config.server.provider.classnames", HelloWorldService.class.getCanonicalName());

    try {
        jettyServer.start();
        jettyServer.join();
    } catch (Exception e){
        System.out.println("Failed running jettyServer with " + e.getMessage());
    } finally {
        jettyServer.destroy();
    }
}

}

Answer 1

其实找到了解决办法。 缺少关键信息是您简单地需要正确的处理程序，将它们放在处理程序列表中，瞧，您就在那里......

大部分是在找到它后取自码头文档

public class JettyServer
{
public static void main(String[] args) throws Exception
{
    // Create a basic Jetty server object that will listen on port 8080.  Note that if you set this to port 0
    // then a randomly available port will be assigned that you can either look in the logs for the port,
    // or programmatically obtain it for use in test cases.
    Server server = new Server(8080);

    // Create the ResourceHandler. It is the object that will actually handle the request for a given file. It is
    // a Jetty Handler object so it is suitable for chaining with other handlers as you will see in other examples.
    ResourceHandler resource_handler = new ResourceHandler();
    // Configure the ResourceHandler. Setting the resource base indicates where the files should be served out of.
    // In this example it is the current directory but it can be configured to anything that the jvm has access to.
    resource_handler.setDirectoriesListed(true);
    resource_handler.setWelcomeFiles(new String[]{ "./html/index.html" });
    resource_handler.setResourceBase(".");

    //Jersey ServletContextHandler
    ServletContextHandler servletContextHandler = new ServletContextHandler(ServletContextHandler.SESSIONS);
    ServletHolder jerseyServlet = servletContextHandler.addServlet(org.glassfish.jersey.servlet.ServletContainer.class, "/api/*");
    jerseyServlet.setInitOrder(0);                                                                                  
    jerseyServlet.setInitParameter("jersey.config.server.provider.classnames", EntryPoint.class.getCanonicalName());

    // Add the ResourceHandler to the server.
    HandlerList handlers = new HandlerList();
    handlers.setHandlers(new Handler[] { resource_handler, servletContextHandler, new DefaultHandler() });
    server.setHandler(handlers);

    // Start things up! By using the server.join() the server thread will join with the current thread.
    // See "http://docs.oracle.com/javase/1.5.0/docs/api/java/lang/Thread.html#join()" for more details.
    server.start();
    server.join();
}

}

帮了我...

Answer 2

我想这就是你想要的：

jerseyServlet.setInitParameter("jersey.config.server.provider.classnames",
             String.join(",", Arrays.asList(EntryPoint.class.getCanonicalName(),
                     HelloWorldService.class.getCanonicalName())));

Answer 3

您没有将ServletHolder 实例添加到ServletContextHandler。

另外两个 servlet 具有相同的 /* 路径，我不确定，但这可能不起作用，尝试归因于不同的路径，看看它是否有效。

做：

context.addServlet(jerseyServlet, "/jersey");

context.addServlet(helloWorldServlet , "/hello");