【发布时间】:2015-04-19 16:18:26
【问题描述】:
以下是计算 Levenstein 最小距离自适应的伪代码。我已经为 python 解码了第一部分,但我无法弄清楚底部,用 *** 表示。
使用动态规划的距离计算算法(伪代码):
First Part:
int function distance(Sequence sequence1, Sequence sequence2)
set length_1 to length of sequence1
set length_2 to length of sequence2
declare distances[length_1+1][length_2+1]
for i from 0 to length_1
set distances[i][0] to i
for j from 0 to length_2
set distances[0][j] to j
// Classical Levenshtein part
for i = 1 to length_1
for j = 1 to length_2
set cost to 0
if (sequence1[i-1] not equal to sequence[j-1])
set cost to 1
set distances[i][j] to minimum of
distances[i-1][j-1] + cost,// Substitution
distances[i][j-1] + 1, // Insertion
distances[i-1][j] + 1 // Deletion
set min_distance to distances[length_1][length_2]
******New Part- Help!*******
// Truncating
for i from 0 to length_1
set min_distance to minimum of min_distance and distances[i][length_2]
// Elongating
for j from 0 to length_2
set min_distance to minimum of min_distance and distances[length_1][j]
return min_distance
【问题讨论】:
-
不分享第一部分的伪代码,为什么不分享代码?
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但这与“古典 Levenshtein 部分”的操作相同,不是吗?遍历一行二维数组并计算一些值的最小值?
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对不起伙计们,我是个菜鸟,我意识到我的翻译代码无论如何都搞砸了。你们中的一个能否救我的命并将整个伪代码翻译成python。最重要的是最后一部分……
标签: python pseudocode