如何遍历列表的列？答案

【问题标题】：How to loop through columns of a list?如何遍历列表的列？
【发布时间】：2019-02-22 08:06:27
【问题描述】：

我正在尝试遍历列表列表。我想找到列表中列的最小值和最大值。

这是列表：

['Afghanistan', 2.66171813, 7.460143566, 0.490880072, 52.33952713, 0.427010864, -0.106340349, 0.261178523]
['Albania', 4.639548302, 9.373718262, 0.637698293, 69.05165863, 0.74961102, -0.035140377, 0.457737535]
['Algeria', 5.248912334, 9.540244102, 0.806753874, 65.69918823, 0.436670482, -0.194670126, 0]
['Argentina', 6.039330006, 9.843519211, 0.906699121, 67.53870392, 0.831966162, -0.186299905, 0.305430293]
['Armenia', 4.287736416, 9.034710884, 0.697924912, 65.12568665, 0.613697052, -0.132166177, 0.246900991]
['Australia', 7.25703764, 10.71182728, 0.949957848, 72.78334045, 0.910550177, 0.301693261, 0.45340696]

我正在尝试遍历从li[1] 到li[-1] 的每一列。

我试过了：

j = 1
small = []
while j < len(li)
    for i in range(0, len(newlist)):
        small.append(newlist[i][j])

    print(max(small))
    print(min(small))
    j = j + 1

输出：

7.25703764
2.66171813

我得到了第一列，但我正在努力循环浏览接下来的列。

【问题讨论】：

您每次都需要学习small列表，以确保它只有当前列的值。

标签： python python-3.x

【解决方案1】：

您可以使用zip。给定您的数据集为my_list：

my_lists = [['Afghanistan', 2.66171813, 7.460143566, 0.490880072, 52.33952713, 0.427010864, -0.106340349, 0.261178523],
['Albania', 4.639548302, 9.373718262, 0.637698293, 69.05165863, 0.74961102, -0.035140377, 0.457737535],
['Algeria', 5.248912334, 9.540244102, 0.806753874, 65.69918823, 0.436670482, -0.194670126, 0],
['Argentina', 6.039330006, 9.843519211, 0.906699121, 67.53870392, 0.831966162, -0.186299905, 0.305430293],
['Armenia', 4.287736416, 9.034710884, 0.697924912, 65.12568665, 0.613697052, -0.132166177, 0.246900991],
['Australia', 7.25703764, 10.71182728, 0.949957848, 72.78334045, 0.910550177, 0.301693261, 0.45340696]]


for t in list(zip(*my_lists))[1:]:
    print(max(t), min(t))

7.25703764 2.66171813
10.71182728 7.460143566
0.949957848 0.490880072
72.78334045 52.33952713
0.910550177 0.427010864
0.301693261 -0.194670126
0.457737535 0

【讨论】：

【解决方案2】：

columns=len(newlist[0])
rows=len(newlist)
for i in range(1,columns):
    for j in range(rows):
        small.append(newlist[j][i])
    print("{}. columuns min value:{} max value:{}".format(i,min(small),max(small)))

【讨论】：

【解决方案3】：

下面的代码使用列表推导创建了一个包含每个列表的最小值和最大值的元组列表，您可以进一步格式化以在每个元组中包含国家/地区名称。

li = [['Afghanistan', 2.66171813, 7.460143566, 0.490880072, 52.33952713, 0.427010864, -0.106340349, 0.261178523],
    ['Albania', 4.639548302, 9.373718262, 0.637698293, 69.05165863, 0.74961102, -0.035140377, 0.457737535],
    ['Algeria', 5.248912334, 9.540244102, 0.806753874, 65.69918823, 0.436670482, -0.194670126, 0],
    ['Argentina', 6.039330006, 9.843519211, 0.906699121, 67.53870392, 0.831966162, -0.186299905, 0.305430293],
    ['Armenia', 4.287736416, 9.034710884, 0.697924912, 65.12568665, 0.613697052, -0.132166177, 0.246900991],
    ['Australia', 7.25703764, 10.71182728, 0.949957848, 72.78334045, 0.910550177, 0.301693261, 0.45340696]]

li2 = [(min(y),max(y)) for y in [[x for x in l[1:]] for l in li]]
print (li2)

【讨论】：