使用bash shell脚本从文件中查找和提取特定字符串后的值？答案

【问题标题】：Find and Extract value after specific String from a file using bash shell script?使用bash shell脚本从文件中查找和提取特定字符串后的值？
【发布时间】：2020-08-04 17:46:18
【问题描述】：

我有一个包含以下详细信息的文件：文件.txt

+----------------------------------------------------+
|                   createtab_stmt                   |
+----------------------------------------------------+
| CREATE EXTERNAL TABLE `dv.par_kst`( |
|   `col1` string,                                   |
|   `col2` string,                                   |
|   `col3` int,                                      |
|   `col4` int,                                      |
|   `col5` string,                                   |
|   `col6` float,                                    |
|   `col7` int,                                      |
|   `col8` string,                                   |
|   `col9` string,                                   |
|   `col10` int,                                     |
|   `col11` int,                                     |
|   `col12` string,                                  |
|   `col13` float,                                   |
|   `col14` string,                                  |
|   `col15` string)                                  |
| PARTITIONED BY (                                   |
|   `part_col1` int,                                 |
|   `part_col2` int)                                 |
| ROW FORMAT SERDE                                   |
|   'org.apache.hadoop.hive.ql.io.parquet.serde.ParquetHiveSerDe'  |
| STORED AS INPUTFORMAT                              |
|   'org.apache.hadoop.hive.ql.io.parquet.MapredParquetInputFormat'  |
| OUTPUTFORMAT                                       |
|   'org.apache.hadoop.hive.ql.io.parquet.MapredParquetOutputFormat' |
| LOCATION                                           |
|   'hdfs://nameservicets1/dv/hdfsdata/par_kst' |
| TBLPROPERTIES (                                    |
|   'spark.sql.create.version'='2.2 or prior',       |
|   'spark.sql.sources.schema.numPartCols'='2',      |
|   'spark.sql.sources.schema.numParts'='1',         |
|   'spark.sql.sources.schema.part.0'='{"type":"struct","fields":[{"name":"col1","type":"string","nullable":true,"metadata":{}},{"name":"col2","type":"string","nullable":true,"metadata":{}},{"name":"col3","type":"integer","nullable":true,"metadata":{}},{"name":"col4","type":"integer","nullable":true,"metadata":{}},{"name":"col5","type":"string","nullable":true,"metadata":{}},{"name":"col6","type":"float","nullable":true,"metadata":{}},{"name":"col7","type":"integer","nullable":true,"metadata":{}},{"name":"col8","type":"string","nullable":true,"metadata":{}},{"name":"col9","type":"string","nullable":true,"metadata":{}},{"name":"col10","type":"integer","nullable":true,"metadata":{}},{"name":"col11","type":"integer","nullable":true,"metadata":{}},{"name":"col12","type":"string","nullable":true,"metadata":{}},{"name":"col13","type":"float","nullable":true,"metadata":{}},{"name":"col14","type":"string","nullable":true,"metadata":{}},{"name":"col15","type":"string","nullable":true,"metadata":{}},{"name":"part_col1","type":"integer","nullable":true,"metadata":{}},{"name":"part_col2","type":"integer","nullable":true,"metadata":{}}]}',  |
|   'spark.sql.sources.schema.partCol.0'='part_col1',  |
|   'spark.sql.sources.schema.partCol.1'='part_col2',  |
|   'transient_lastDdlTime'='1587487456')            |
+----------------------------------------------------+

我想从上面的文件中提取 PARTITIONED BY 详细信息。

Desired output :

part_col1 , part_col2

这些 PARTITIONED BY 不是固定的，意味着对于其他一些文件它可能包含 3 个或更多，所以我想提取所有 PARTITIONED BY。

PARTITIONED BY 和 ROW FORMAT SERDE 之间的所有值，删除空格“`”和数据类型！

您能帮我解决这个问题吗？

【问题讨论】：

标签： linux shell perl unix sh

【解决方案1】：

sed -nr '/PARTITIONED BY/,/ROW FORMAT SERDE/p' a.txt|sed -nr '/`/p'|cut -d '`' -f 2|xargs -n 1 echo -n " "

【讨论】：

并且不是在 file.txt 中有记录，我必须执行如下： par_col=beeline --silent -u "$BEELINE_URL" -e "$sql" where sql="show create table dvs_wk.par_kst" Par_col 有上述结果但是当我像这样：result=sed -n '/PARTITIONED BY/,/ROW FORMAT SERDE/p' $par_col | sed -n '//p'|cut -d '' -f 2|xargs -n 1 echo -n " " 它给了我一个错误。
sed 打印 PARTITIONED BY 和 ROW FORMAT SERDE 之间的所有字符串（包括它们），然后另一个 sed 仅打印带有“" character, than cut command split string in column by "”的字符串并打印第二列（您的号码），然后 xargs 抓取所有数字并用空格作为分隔符打印它们。可能不是最好的管道，但它适用于您的示例。

【解决方案2】：

my $text = do { local $/; <DATA> };

my @partitioned = ();

$text=~s#PARTITIONED BY\s*\(([^\(\)]*)\)# my $fulcontent=$1; 
push (@partitioned, $1) while($fulcontent=~m/\`([^\`]+)\`/g);
($fulcontent);
#egs;

print join "\, ", @partitioned;

输出：

part_col1，part_col2

【讨论】：

【解决方案3】：

当您的结果布局无关紧要时，您可以要求sed 考虑开始和结束标记之间的行，并且仅在可以在 2 个反引号之间找到字段时打印这样的行。

sed -rn '/PARTITIONED BY/,/ROW FORMAT/s/.*`(.*)`.*/\1/p' file.txt

可以根据需要将结果组合成一行

printf "%s , " $(sed -rn '/PARTITIONED BY/,/ROW FORMAT/s/.*`(.*)`.*/\1 /p' file.txt) |
   sed 's/ , $/\n/'

【讨论】：

【解决方案4】：

小perl脚本

将整个文件读入$data变量
在PARTITIONED BY (....)之间全选
仅选择 `
打印结果加入,

use strict;
use warnings;
use feature 'say';

my $data = do { local $/; <> };
my $re   = 'PARTITIONED BY \((.*?)\)';

$data =~ /$re/sg;

my @part = $1 =~ /`(.*?)`/sg;

say join ', ', @part;

【讨论】：