从 Unity 向 Arduino 发送许多变量

Question

我正在尝试向我的“masterArduino”发送许多整数。 因为 SerialPort 对象只发送字符串。我尝试了很多方法，包括：

• 从整数创建字符串（不起作用，因为 string.length 的大小是动态的）。
• 然后我尝试将这些整数转换为字符，这是因为所有值都在 0-255 之间，然后将字符放入字符串并发送。

这类作品。但是，我认为 char 世界中的 0 没有任何价值。所以数据不对。但一定有更好的办法吗？

void sendInfo() {
    for (var i = 0; i < peltiers.Length; i++) {
        char tempHot = (char) peltiers[i].GetComponent<Peltier>().hot;
        char charTemp = (char) peltiers[i].GetComponent<Peltier>().temp;
        peltierInfo += tempHot.ToString();           
        peltierInfo += charTemp.ToString();                  
    } 
    sp.WriteLine(peltierInfo);
    Debug.Log(peltierInfo);
    sp.BaseStream.Flush();
    peltierInfo = "";         
}

任何帮助将不胜感激！谢谢！

Arduino 代码：

void loop() {
    int serialIndex = 0;  
    int i2cIndex = 0; 
    while (0 < Serial.available()) { // loop through all the received bytes 
    char bufferByte = 0;     
    bufferByte = Serial.read();
    serialBuffer[serialIndex] = (byte) bufferByte;  // put current index byte in array      
    serialIndex ++;                    // add index. 
    if (serialIndex%12==0 && serialIndex != 0) {
          sendBytes(0);      
       }
    } 
     //sendBytes(0);  
     delay(50);
}

void sendBytes(int slave) {
    byte i2cBuffer[12];
    int bufferIndex = slave * 12;
    for (int i = 0; i < 12; i++) {
        i2cBuffer[i] = serialBuffer[i + bufferIndex];
    }
    Wire.beginTransmission(slave+1);
    Wire.write(i2cBuffer, 12);
    Wire.endTransmission();  
}

Answer 1

为了能够发送任何整数，首先将它们编码成一个字符串，用一些东西（例如'\0' char）分隔它们，然后解码该字符串。

void sendInfo() {
    ...
    peltierInfo += peltiers[i].GetComponent<Peltier>().hot.ToString();
    peltierInfo += '\0';
    peltierInfo += peltiers[i].GetComponent<Peltier>().temp.ToString();
    peltierInfo += '\0';
    ...
}

void loop() {
    int serialIndex = 0;  
    int i2cIndex = 0;
    // set to how many digits there can be in an incoming number plus 1
    int maxNumberLen = 20; 
    char buffer[20];
    // position at which we now put a char that makes up our number
    char* currentCharPtr = buffer;
    while (0 < Serial.available()) { // loop through all the received bytes 
       char bufferByte = 0;     
       bufferByte = Serial.read();
       *currentCharPtr = bufferByte;
       // move pointer forward
       currentCharPtr ++;
       // end of a number in string
       if (bufferByte == '\0') {
           printf("Got number %s\n", buffer);
           // atoi parses string to int
           serialBuffer[serialIndex] = atoi(buffer); 
           serialIndex ++;                    
           if(serialIndex%12==0 && serialIndex != 0){
              sendBytes(0);
           }
           // fill buffer with zeros after we found a number
           memset(buffer, 0, 20);
           currentCharPtr = buffer;
       }
    } 
     //sendBytes(0);  
     delay(50);

 }

Answer 2

感谢您的回复，您的回答正是我的工作方式。我只是做的略有不同，没有时间上传这篇文章。哪种方式更好，还是只是口味问题？

团结

 void sendInfo()
{
    for (int i = 0; i < peltiers.Length; i++)
    {
        peltierInfo += ",";
        peltierInfo += peltiers[i].GetComponent<Peltier>().hot.ToString();
        peltierInfo += ",";
        peltierInfo += peltiers[i].GetComponent<Peltier>().temp.ToString("D3");
    }
    //Debug.Log(peltierInfo);
    sp.WriteLine(peltierInfo);
    sp.BaseStream.Flush();
    peltierInfo = "";
}

阿杜诺

void loop() {
   int serialIndex = 0;
   if(Serial.available() > 0){     
     while (0 < Serial.available()) {            // loop through all the received bytes 
        String bufferString;
        uint8_t bufferInt;
        bufferString = Serial.readStringUntil(','); 
        bufferInt = bufferString.toInt();      
        serialBuffer[serialIndex] = bufferInt;  // put current index byte in array      
        serialIndex ++;                          // add index. 
     }     
     sendBytes(0); 
   }
   delay(50);
}

感谢您的帮助！