如何为子菜单项创建键盘快捷键

Question

我正在使用 wpf。我遇到的问题是为菜单项创建键盘快捷键。 如何通过键盘快捷键调用子菜单项。 任何人都可以对此有所了解吗？请帮助我..提前谢谢.. 我的 .xaml 文件是

    <MenuItem Header="_Open file" Name="open" IsCheckable="True"  Click="file_click"  InputGestureText="ctrl+o">

 <MenuItem.InputBindings>
   <KeyBinding Key="O" Modifiers="control"/>
                </MenuItem.InputBindings>
            </MenuItem>

我在 .cs 文件中的点击事件是

   private void file_click(object sender, RoutedEventArgs e)
       {



        OpenFileDialog ofd;
        ofd = new OpenFileDialog();
        ofd.AddExtension = true;
        ofd.DefaultExt = "*.*";
        ofd.Filter = "media (*.*)|*.*";
        ofd.ShowDialog();
        mediaElement1.Source = new Uri(ofd.FileName);
        listBox1.Items.Add(ofd.SafeFileName);
        mediaElement1.Play();



    }

Answer 1

在你的 XAML 中试试这个：

<Window.CommandBindings>
    <CommandBinding Command="Open" Executed="CommandBinding_Executed" />
</Window.CommandBindings>
<Window.InputBindings>
    <KeyBinding Command="Open" Key="O" Modifiers="control" />
</Window.InputBindings>
<Grid>
    <MenuItem Header="_Open file" Name="open" IsCheckable="True" Command="Open"  InputGestureText="ctrl+o" DockPanel.Dock="Top">            
    </MenuItem>        
</Grid>

后面的代码：

 private void CommandBinding_Executed(object sender, ExecutedRoutedEventArgs e) {
        OpenFileDialog ofd;
        ofd = new OpenFileDialog();
        ofd.AddExtension = true;
        ofd.DefaultExt = "*.*";
        ofd.Filter = "media (*.*)|*.*";
        ofd.ShowDialog();
    }