如何从另一个 IntentService 中的 IntentService 接收值？答案

【问题标题】：How to receive values from an IntentService in another IntentService?如何从另一个 IntentService 中的 IntentService 接收值？
【发布时间】：2015-11-17 21:34:38
【问题描述】：

我有这个 IntentService (HttpService)，它从 web 服务获取原始 json 数据：

public class HttpService extends IntentService {

    public static final String BROADCAST_ACTION = "com.example.HttpService";

    public HttpService() {
        super("HttpService");
    }

    @Override
    protected void onHandleIntent(Intent intent) {

        //code to get a String with jsonData


         //Then I send a broadcast
         Intent broadcastHttpResponseIntent = new Intent();
         broadcastHttpResponseIntent.setAction(BROADCAST_ACTION);
         broadcastHttpResponseIntent.putExtra("jsonData", jsonData);

         sendBroadcast(broadcastHttpResponseIntent);

    }
}

现在从使用 HttpService 的 IntentService 我正在尝试获取广播：

public class RestaurantModel extends IntentService {

    public static final String BROADCAST_ACTION = "com.example.RestaurantModel";

    public RestaurantModel() {
        super("RestaurantModel");
    }

    @Override
    protected void onHandleIntent(Intent intent) {
        Log.v("RestaurantModel", "onHandleIntent");

        BroadcastReceiver httpBroadcastReceiver = new BroadcastReceiver() {
            @Override
            public void onReceive(Context context, Intent intent) {
                Log.v("RestaurantModel", "onReceive");

                String jsonResponse = intent.getStringExtra("jsonData");

            }
        };

        Intent getRestaurantsJsonIntent = new Intent(RestaurantModel.this, HttpService.class);
        getRestaurantsJsonIntent.putExtra("urlRestaurants", intent.getStringExtra("urlRestaurants"));
        startService(getRestaurantsJsonIntent);

        registerReceiver(httpBroadcastReceiver, new IntentFilter(HttpService.BROADCAST_ACTION));
    }
}

所以我收到了这个错误：

RestaurantModel 泄露了最初在此处注册的 IntentReceiver com.example.RestaurantModel$1@42374590。您是否错过了对 unregisterReceiver() 的调用？

所以我尝试注销接收器，但似乎需要一个上下文来注销接收器。

如何从一个 IntentService 接收值到另一个 IntentService？

【问题讨论】：

标签： android android-intent android-activity android-service android-intentservice

【解决方案1】：

最好的答案是：只有一个IntentService。

下一个最佳答案是：完全摆脱广播内容，让第一个 IntentService 调用 startService() 来启动第二个 IntentService。

【讨论】：

【解决方案2】：

同意@CommonsWare，如果您想在 IntentService 中使用 BroadcaseReceiver，请在 onCreate 方法中注册它并在 onDestroy 方法中取消注册。

public class RestaurantModel extends IntentService {

public static final String BROADCAST_ACTION = "com.example.RestaurantModel";

private BroadcastReceiver httpBroadcastReceiver;

public RestaurantModel() {
    super("RestaurantModel");
}

@Override
public void onCreate() {
    super.onCreate();
     httpBroadcastReceiver = new BroadcastReceiver() {
        @Override
        public void onReceive(Context context, Intent intent) {
            Log.v("RestaurantModel", "onReceive");

            String jsonResponse = intent.getStringExtra("jsonData");

        }
    };

    LocalBroadcastManager.getInstance(getApplicationContext()).registerReceiver(httpBroadcastReceiver);
}

@Override
public void onDestroy() {
    super.onDestroy();
    LocalBroadcastManager.getInstance(getApplicationContext()).unregisterReceiver(httpBroadcastReceiver);
}

@Override
protected void onHandleIntent(Intent intent) {
    Log.v("RestaurantModel", "onHandleIntent");


    Intent getRestaurantsJsonIntent = new Intent(RestaurantModel.this, HttpService.class);
    getRestaurantsJsonIntent.putExtra("urlRestaurants", intent.getStringExtra("urlRestaurants"));
    startService(getRestaurantsJsonIntent);


}

}

【讨论】：