从 3G/WiFi 获取坐标答案

【问题标题】：Get coordinates from 3G/WiFi从 3G/WiFi 获取坐标
【发布时间】：2014-10-08 09:39:45
【问题描述】：

在我的应用程序中，我有一个对话框。单击是时，它会发送一个带有经纬度作为参数的 HTTP 请求。截至目前，该应用程序从 GPS_PROVIDER 检索这些信息，但如果 GPS 不可用，我希望它也从 3G 和 WiFi 获取坐标。有人可以帮忙吗？

AlertDialog ad = new AlertDialog.Builder(getActivity()).setTitle("Dialog title")
                .setMessage("Do you want to send a request?")
                .setPositiveButton("Yes",
                        new DialogInterface.OnClickListener() {
                    public void onClick(DialogInterface dialog, int whichButton) {
                        if (locationManager
                                .isProviderEnabled(LocationManager.GPS_PROVIDER) && location!=null) {
//do HTTP request stuff
                                if (isOnline()) {

                                if (response.getStatusLine().getStatusCode()==200) {
                                    Toast toast = Toast.makeText(getActivity(), "Request has been sent. Your coordinates are: " + Double.toString(location.getLatitude()) + " (Latitude) " + Double.toString(location.getLongitude()) + " (Longitude).", Toast.LENGTH_LONG);
                                    toast.show();
                                }
                                else {
                                    Toast toast = Toast.makeText(getActivity(), "Request has NOT been sent.", Toast.LENGTH_LONG);
                                    toast.show();
                                }
                            }
                            else {
                                Toast toast = Toast.makeText(getActivity(), "Network is not available.", Toast.LENGTH_LONG);
                                toast.show();
                            }
                        }
                        else {
                            Toast toast = Toast.makeText(getActivity(), "GPS is not available.", Toast.LENGTH_LONG);
                            toast.show();
                        }
                    }
                }).setNegativeButton("No", new DialogInterface.OnClickListener() {
                    public void onClick(DialogInterface dialog, int whichButton) {
                        Toast toast = Toast.makeText(getActivity(), "Request has not been sent.", Toast.LENGTH_LONG);
                        toast.show();
                    }
                }).create();
        ad.show();
}
public boolean isOnline() {
    ConnectivityManager cm =
            (ConnectivityManager) getActivity().getSystemService(Context.CONNECTIVITY_SERVICE);

    return cm.getActiveNetworkInfo() != null && 
            cm.getActiveNetworkInfo().isConnectedOrConnecting();
}

【问题讨论】：

标签： java android gps

【解决方案1】：

你可以用这个

private Location getLocation() {
    LocationManager manager = (LocationManager) getSystemService(Context.LOCATION_SERVICE);
    if (manager.isProviderEnabled(LocationManager.NETWORK_PROVIDER)) {
        return manager.getLastKnownLocation(LocationManager.NETWORK_PROVIDER);
    } else if (manager.isProviderEnabled(LocationManager.GPS_PROVIDER)) {
        return manager.getLastKnownLocation(LocationManager.GPS_PROVIDER);
    }
    return null;
}

如果只使用基于网络的位置，请使用这个

<uses-permission android:name="android.permission.ACCESS_COARSE_LOCATION"/>

对于基于 GPS 的位置，这个

<uses-permission android:name="android.permission.ACCESS_FINE_LOCATION"/>

【讨论】：

谢谢！很有帮助。