在创建新节点之前读取文件时检查前面的一行

Question

file being read

outPut of said file

我正在尝试从文件中读取数据并将其数据存储在我的链表中。我遇到的问题是，当我读取包含第二个地址的人的信息时，我的函数仅使用包含两个地址的数据更新我的链表。注意：打印我的链接列表时，它是相反的顺序，因为在每个节点之前。注意底部的 5 个打印语句如何包含 1 个地址，这些是我从文件中检索的前 5 行。一旦函数到达包含两个地址的第 6 行，它就无法使用仅包含 1 个地址的数据更新我的列表。但是，它会继续更新我的列表中包含 2 个地址的两个数据。

void AddressBook::readFile(string fileName) {

    ifstream f(fileName);

    string firstName = "", lastName, phoneNumber, buildingNumber, street, city, state, zipCode, buildingNumber_2, street_2, city_2, state_2, zipCode_2, entry;
    bool twoAddr = false;

    if (!f.is_open()) { die("file not open"); }

    while (f >> entry) {
        if (isdigit(entry[0])) {
            buildingNumber_2 = entry;
            f >> street_2 >> city_2 >> state_2 >> zipCode_2;
            addEntry(Person(firstName, lastName, phoneNumber, Address(buildingNumber, street, city, state, zipCode), Address(buildingNumber_2, street_2, city_2, state_2, zipCode_2)));
                twoAddr = true;
        }
        else {
            if (firstName != "" && !twoAddr) {
                addEntry(Person(firstName, lastName, phoneNumber, Address(buildingNumber, street, city, state, zipCode)));
                twoAddr = false;
            }
            firstName = entry;
            f >> lastName >> phoneNumber >> buildingNumber >> street >> city >> state >> zipCode;
        }
    }
}

Answer 1

尝试实现这个算法：

for (;;) {
  line = file.readline();
  if (is_person_line(line))
    addEntry(create_person(line));
  else if (is_address_only(line))
    entries[-1].add_address(create_address(line));
}

它还应该使您的代码更清晰。