【发布时间】：2013-03-11 14:18:37
【问题描述】：
我已经看到了一些没有自动接线的解决方案，但我正在尝试让它与自动接线一起使用。自上周以来我一直在尝试这个，但没有找到适合我的解决方案，可能是我没有正确实施它，所以任何帮助都会很棒。
我有一个属性文件myprops.properties：
Wsdl=someurl
UserName=admin
UserPassword=ENC(encriptedpassword)
在我的 servlet.xml 文件中我替换了
<context:property-placeholder location="classpath*:myprops.properties" />
与
<bean id="propertyPlaceholderConfigurer"
class="org.jasypt.spring.properties.EncryptablePropertyPlaceholderConfigurer">
<constructor-arg ref="configurationEncryptor" />
<property name="location" value="classpath:myprops.properties" />
</bean>
<bean id="configurationEncryptor" class="org.jasypt.encryption.pbe.StandardPBEStringEncryptor">
<property name="config" ref="environmentVariablesConfiguration" />
</bean>
<bean id="environmentVariablesConfiguration"
class="org.jasypt.encryption.pbe.config.EnvironmentStringPBEConfig">
<property name="algorithm" value="PBEWithMD5AndDES" />
<property name="passwordEnvName" value="APP_ENCRYPTION_PASSWORD" />
</bean>
在我的 service.java 中，我像这样自动连接这些值：
@Autowired
public void setUserPassword(@Value("${UserPassword}") String userPassword) {
this.userPassword = userPassword;
}
@Autowired
public void setUserName(@Value("${UserName}") String userName) {
this.userName = userName;
}
@Autowired
public void setWsdl(@Value("${Wsdl}") String wsdl) {
this.wsdl = wsdl;
}
这在我没有加密密码时有效，即UserPassword=nonencriptedpassword
但是一旦我将它加密并使用 ENC() 我就会收到以下错误
weblogic.application.ModuleException:
at weblogic.servlet.internal.WebAppModule.startContexts(WebAppModule.java:1510)
at weblogic.servlet.internal.WebAppModule.start(WebAppModule.java:482)
at weblogic.application.internal.flow.ModuleStateDriver$3.next(ModuleStateDriver.java:425)
at weblogic.application.utils.StateMachineDriver.nextState(StateMachineDriver.java:52)
at weblogic.application.internal.flow.ModuleStateDriver.start(ModuleStateDriver.java:119)
Truncated. see log file for complete stacktrace
Caused By: java.lang.NullPointerException
at org.jasypt.encryption.pbe.config.SimplePBEConfig.getPasswordCharArray(SimplePBEConfig.java:434)
at org.jasypt.encryption.pbe.StandardPBEByteEncryptor.resolveConfigurationPassword(StandardPBEByteEncryptor.java:740)
at org.jasypt.encryption.pbe.StandardPBEByteEncryptor.initialize(StandardPBEByteEncryptor.java:590)
at org.jasypt.encryption.pbe.StandardPBEStringEncryptor.initialize(StandardPBEStringEncryptor.java:553)
at org.jasypt.encryption.pbe.StandardPBEStringEncryptor.decrypt(StandardPBEStringEncryptor.java:705)
Truncated. see log file for complete stacktrace
这可能是一些我不知道或忽略的愚蠢简单的事情，但我已经尝试关注Jasypt wiki 和网站上的教程以及xmx1024 和jayway 上的教程，我确定我使用自动接线找到了一个，但我似乎无法再次找到它。
仅供参考：我使用的是 spring 3.0.4、Spring Security 3.0.4 和 jasypt 1.9
任何帮助都会很棒
更新
我已将环境变量APP_ENCRYPTION_PASSWORD 设置为等于纯文本密码，并将属性文件中的密码设置为返回值
encrypt input=plaintextpassword password=APP_ENCRYPTION_PASSWORD
我现在得到错误
<11-Mar-2013 16:33:54 o'clock GMT> <Warning> <HTTP> <BEA-101162> <User defined listener org.springframework.web.context.ContextLoaderListener failed: org.jasypt.exceptions.EncryptionOperationNotPossibleException.
org.jasypt.exceptions.EncryptionOperationNotPossibleException
at org.jasypt.encryption.pbe.StandardPBEByteEncryptor.decrypt(StandardPBEByteEncryptor.java:981)
at org.jasypt.encryption.pbe.StandardPBEStringEncryptor.decrypt(StandardPBEStringEncryptor.java:725)
at org.jasypt.properties.PropertyValueEncryptionUtils.decrypt(PropertyValueEncryptionUtils.java:72)
at org.jasypt.spring3.properties.EncryptablePropertyPlaceholderConfigurer.convertPropertyValue(EncryptablePropertyPlaceholderConfigurer.java:109)
at org.springframework.beans.factory.config.PropertyResourceConfigurer.convertProperty(PropertyResourceConfigurer.java:112)
Truncated. see log file for complete stacktrace
>
<11-Mar-2013 16:33:54 o'clock GMT> <Error> <Deployer> <BEA-149265> <Failure occurred in the execution of deployment request with ID '1363019632631' for task '0'. Error is: 'weblogic.application.ModuleException: '
weblogic.application.ModuleException:
at weblogic.servlet.internal.WebAppModule.startContexts(WebAppModule.java:1510)
at weblogic.servlet.internal.WebAppModule.start(WebAppModule.java:482)
at weblogic.application.internal.flow.ModuleStateDriver$3.next(ModuleStateDriver.java:425)
at weblogic.application.utils.StateMachineDriver.nextState(StateMachineDriver.java:52)
at weblogic.application.internal.flow.ModuleStateDriver.start(ModuleStateDriver.java:119)
Truncated. see log file for complete stacktrace
Caused By: org.jasypt.exceptions.EncryptionOperationNotPossibleException
at org.jasypt.encryption.pbe.StandardPBEByteEncryptor.decrypt(StandardPBEByteEncryptor.java:981)
at org.jasypt.encryption.pbe.StandardPBEStringEncryptor.decrypt(StandardPBEStringEncryptor.java:725)
at org.jasypt.properties.PropertyValueEncryptionUtils.decrypt(PropertyValueEncryptionUtils.java:72)
at org.jasypt.spring3.properties.EncryptablePropertyPlaceholderConfigurer.convertPropertyValue(EncryptablePropertyPlaceholderConfigurer.java:109)
at org.springframework.beans.factory.config.PropertyResourceConfigurer.convertProperty(PropertyResourceConfigurer.java:112)
Truncated. see log file for complete stacktrace
>
<11-Mar-2013 16:33:54 o'clock GMT> <Error> <Deployer> <BEA-149202> <Encountered an exception while attempting to commit the 1 task for the application 'adminUI_EA'.>
<11-Mar-2013 16:33:54 o'clock GMT> <Warning> <Deployer> <BEA-149004> <Failures were detected while initiating deploy task for application 'adminUI_EA'.>
<11-Mar-2013 16:33:54 o'clock GMT> <Warning> <Deployer> <BEA-149078> <Stack trace for message 149004
weblogic.application.ModuleException: :org.jasypt.exceptions.EncryptionOperationNotPossibleException:null
at org.jasypt.encryption.pbe.StandardPBEByteEncryptor.decrypt(StandardPBEByteEncryptor.java:981)
at org.jasypt.encryption.pbe.StandardPBEStringEncryptor.decrypt(StandardPBEStringEncryptor.java:725)
at org.jasypt.properties.PropertyValueEncryptionUtils.decrypt(PropertyValueEncryptionUtils.java:72)
at org.jasypt.spring3.properties.EncryptablePropertyPlaceholderConfigurer.convertPropertyValue(EncryptablePropertyPlaceholderConfigurer.java:109)
at org.springframework.beans.factory.config.PropertyResourceConfigurer.convertProperty(PropertyResourceConfigurer.java:112)
Truncated. see log file for complete stacktrace
>
密码加密是通过以下方式完成的
C:\Users\jonnie\Desktop\jasypt-1.9.0\bin>encrypt input=****** password=APP_ENCRYPTION_PASSWORD
----ENVIRONMENT-----------------
Runtime: Sun Microsystems Inc. Java HotSpot(TM) 64-Bit Server VM 20.12-b01
----ARGUMENTS-------------------
input: *******
password: APP_ENCRYPTION_PASSWORD
----OUTPUT----------------------
****encriptedPassword****
【问题讨论】：
-
不要自动装配，而是尝试只为每个属性设置类字段并用
@Value注释它们。 -
@SotiriosDelimanolis 但是我应该能够使用 Autowire 来完成此任务吗？
-
我不确定。
@Autowired应该与 Spring bean 一起使用。您的字符串不会在任何地方声明为 bean。@Value用于为字段提供默认值，我认为这就是您要寻找的。span> -
我对春天不是很有经验，而且不久前有点陷入困境，所以请原谅我的无知，但如果我删除
@Autowired并将@Value留在原处，那就是什么意思？ -
删除
@Autowired，去掉setter方法，只用@Value注释你的私有字段。您可以保留设置器，但注释您的字段而不是注释方法的参数。
标签： java spring spring-security jasypt