【发布时间】:2019-10-03 21:13:12
【问题描述】:
在这个程序中,我正在读取、操作和编写二进制位图文件。我正在尝试使用 C 样式文件来读取和写入这些文件。我还使用 new() 动态地将内存分配到堆上并删除,以便将该内存块写入另一个文件。 我认为当我在 for 循环中读取和写入二进制文件时遇到问题。在查看了我的输出文件后,我不知何故被 File 和 Info 标头覆盖。我只需要帮助理解为什么会这样。我所有的其他代码都应该没问题。
#include <cstdint>
#include <cstdio>
#pragma pack(push, 2)
struct BitmapFileHeader {
uint16_t type;
uint32_t size;
uint16_t reserved_1;
uint16_t reserved_2;
uint32_t offset;
};
struct BitmapInfoHeader {
uint32_t size;
uint32_t width;
uint32_t height;
uint16_t planes;
uint16_t bitcount;
uint32_t compression;
uint32_t imagesize;
uint32_t x_pixels_per_meter;
uint32_t y_pixels_per_meter;
uint32_t color_used;
uint32_t color_important;
};
#pragma pack(pop)
struct Pixel {
uint8_t blue;
uint8_t green;
uint8_t red;
};
int main(int argc, char* argv[])
{
if(argc != 3) {
printf("Usage : %s input_file output_file\n", argv[0]);
return 1;
}
FILE *fin;
FILE *fout;
BitmapFileHeader bfh;
BitmapInfoHeader bih;
fin = fopen(argv[1], "rb");
if (nullptr == fin) {
perror(argv[1]);
return -1;
}
if (sizeof(BitmapFileHeader) != fread(
&bfh,
1,
sizeof(bfh),
fin
)) {
printf("Unable to read bitmap file header. \n");
return -2;
}
if (sizeof(BitmapInfoHeader) != fread(
&bih,
1,
sizeof(bih),
fin
)) {
printf("Unable to read bitmap info header. \n");
return -3;
}
printf("Size of File Header = %lu\n", sizeof(BitmapFileHeader));
int8_t first = (bfh.type >> 8) & 0xff;
int8_t second = bfh.type & 0xff;
if ( (first != 'M') && (second != 'B') ){
printf("Input file is not a Bitmap file. \n");
return -4;
}
printf("File type = %c%c\n", first, second);
printf("File size = %u\n", bfh.size);
printf("File offset = %u\n", bfh.offset);
printf("File width = %u\n", bih.width);
printf("Info size = %u\n", bih.size);
uint32_t padding_bytes = 0;
uint32_t row_bytes_final = bih.width * sizeof(Pixel);
uint32_t row_bytes_initial = row_bytes_final;
do{
uint32_t rem = row_bytes_final % 4;
if (rem != 0) {
row_bytes_final += 1;
}
padding_bytes = row_bytes_final - row_bytes_initial;
} while( (row_bytes_final % 4) != 0);
fseek(fin, bfh.offset, SEEK_SET);
Pixel *p = new Pixel[bih.height * bih.width];
for (uint32_t i = 0; i < (bih.height); i++) {
for (uint32_t j = 0; j < bih.width; j++) {
fread(&p[i], 1, sizeof(p), fin);
i++;
//Something I don't understand is wrong here.
}
fseek(fin, padding_bytes, SEEK_CUR);
}
fclose(fin);
fout = fopen(argv[2], "wb");
if(nullptr == fout) {
perror(argv[2]);
return -5;
}
if( sizeof(BitmapFileHeader) != fwrite(
&bfh,
1,
sizeof(bfh),
fout
)) {
printf("Unable to write bitmap file header.\n");
return -6;
}
if( sizeof(BitmapInfoHeader) != fwrite(
&bih,
1,
sizeof(bih),
fout
)) {
printf("Unable to write bitmap info header.\n");
return -7;
}
fseek(fout, bfh.offset, SEEK_SET);
for (uint32_t i = 0; i < (bih.height) ; i++) {
for (uint32_t j = 0; i < bih.width; j++) {
fwrite(&p[i], 1, sizeof(p), fout);
i++;
//same problem
}
fseek(fout, padding_bytes, SEEK_CUR);
}
fclose(fout);
delete p;
//fseek(fin, bfh.offset, SEEK_SET);
//Pixel p;
//fread(&p, 1, sizeof(p), fin);
//printf("R = %u, G = %u, B = %u\n", p.red, p.green, p.blue);
return 0;
}
如果我将文件指针移动到偏移量,如何覆盖输出文件的标题?
【问题讨论】:
-
由于结构填充,您可能无法读取和写入原始结构。尝试单独阅读每个组件,以确保不会错位。
-
这似乎是一个错字。
fwrite(&p[i], 1, sizeof(p), fout);应该是fwrite(&p[i], 1, sizeof(p[i]), fout);它必须是sizeof(p[i]),而不是sizeof(p)。 -
“#Pragma pack(push, 2)”和“Pragma pack(pop)”不能解决这个问题吗?
-
@tadman:为什么在读写是相同程序时填充不同?
-
我认为这可以解决问题,但我的输出文件与输入文件大不相同;我用 for 循环进行迭代的方式可能有问题。
标签: c++ binaryfiles