比较 Objective-C 中的版本号

Question

我正在编写一个应用程序来接收包含项目和版本号的数据。这些数字的格式类似于“1.0.1”或“1.2.5”。如何比较这些版本号？我认为它们必须首先格式化为字符串，不是吗？我有哪些选项可以确定“1.2.5”在“1.0.1”之后？

Answer 1

这是比较版本的最简单方法，记住 "1"

NSString* requiredVersion = @"1.2.0";
NSString* actualVersion = @"1.1.5";

if ([requiredVersion compare:actualVersion options:NSNumericSearch] == NSOrderedDescending) {
  // actualVersion is lower than the requiredVersion
}

Answer 2

我将添加我的方法，它将严格的数字版本（无 a、b、RC 等）与任意数量的组件进行比较。

+ (NSComparisonResult)compareVersion:(NSString*)versionOne toVersion:(NSString*)versionTwo {
    NSArray* versionOneComp = [versionOne componentsSeparatedByString:@"."];
    NSArray* versionTwoComp = [versionTwo componentsSeparatedByString:@"."];

    NSInteger pos = 0;

    while ([versionOneComp count] > pos || [versionTwoComp count] > pos) {
        NSInteger v1 = [versionOneComp count] > pos ? [[versionOneComp objectAtIndex:pos] integerValue] : 0;
        NSInteger v2 = [versionTwoComp count] > pos ? [[versionTwoComp objectAtIndex:pos] integerValue] : 0;
        if (v1 < v2) {
            return NSOrderedAscending;
        }
        else if (v1 > v2) {
            return NSOrderedDescending;
        }
        pos++;
    }

    return NSOrderedSame;
}

Answer 3

这是对 Nathan de Vries 答案的扩展，用于解决 1

首先，我们可以使用NSString 类别解决版本字符串中多余“.0”的问题：

@implementation NSString (VersionNumbers)
- (NSString *)shortenedVersionNumberString {
    static NSString *const unnecessaryVersionSuffix = @".0";
    NSString *shortenedVersionNumber = self;

    while ([shortenedVersionNumber hasSuffix:unnecessaryVersionSuffix]) {
        shortenedVersionNumber = [shortenedVersionNumber substringToIndex:shortenedVersionNumber.length - unnecessaryVersionSuffix.length];
    }

    return shortenedVersionNumber;
}
@end

使用上述NSString 类别，我们可以缩短版本号以删除不必要的.0

NSString* requiredVersion = @"1.2.0";
NSString* actualVersion = @"1.1.5";

requiredVersion = [requiredVersion shortenedVersionNumberString]; // now 1.2
actualVersion = [actualVersion shortenedVersionNumberString]; // still 1.1.5

现在我们仍然可以使用 Nathan de Vries 提出的精美简单的方法：

if ([requiredVersion compare:actualVersion options:NSNumericSearch] == NSOrderedDescending) {
  // actualVersion is lower than the requiredVersion
}

Answer 4

我自己做的，使用类别..

来源..

@implementation NSString (VersionComparison)
- (NSComparisonResult)compareVersion:(NSString *)version{
    NSArray *version1 = [self componentsSeparatedByString:@"."];
    NSArray *version2 = [version componentsSeparatedByString:@"."];
    for(int i = 0 ; i < version1.count || i < version2.count; i++){
        NSInteger value1 = 0;
        NSInteger value2 = 0;
        if(i < version1.count){
            value1 = [version1[i] integerValue];
        }
        if(i < version2.count){
            value2 = [version2[i] integerValue];
        }
        if(value1  == value2){
            continue;
        }else{
            if(value1 > value2){
                return NSOrderedDescending;
            }else{
                return NSOrderedAscending;
            }
        }
    }
    return NSOrderedSame;
}

测试..

NSString *version1 = @"3.3.1";
NSString *version2 = @"3.12.1";
NSComparisonResult result = [version1 compareVersion:version2];
switch (result) {
    case NSOrderedAscending:
    case NSOrderedDescending:
    case NSOrderedSame:
         break;
    }

Answer 5

Sparkle（MacOS 上最流行的软件更新框架）有一个 SUStandardVersionComparator 类来执行此操作，并且还考虑了内部版本号和 beta 标记。 IE。它正确地比较了1.0.5 > 1.0.5b7 或2.0 (2345) > 2.0 (2100)。该代码仅使用 Foundation，因此在 iOS 上也可以正常工作。

Answer 6

查看我在 github 上实现简单版本检查的 NSString 类别； https://github.com/stijnster/NSString-compareToVersion

[@"1.2.2.4" compareToVersion:@"1.2.2.5"];

这将返回一个 NSComparisonResult，它比使用更准确；

[@"1.2.2" compare:@"1.2.2.5" options:NSNumericSearch]

还添加了助手；

[@"1.2.2.4" isOlderThanVersion:@"1.2.2.5"];
[@"1.2.2.4" isNewerThanVersion:@"1.2.2.5"];
[@"1.2.2.4" isEqualToVersion:@"1.2.2.5"];
[@"1.2.2.4" isEqualOrOlderThanVersion:@"1.2.2.5"];
[@"1.2.2.4" isEqualOrNewerThanVersion:@"1.2.2.5"];

Answer 7

Swift 2.2 版本：

let currentStoreAppVersion = "1.10.2"
let minimumAppVersionRequired = "1.2.2"
if currentStoreAppVersion.compare(minimumAppVersionRequired, options: NSStringCompareOptions.NumericSearch) ==
            NSComparisonResult.OrderedDescending {
            print("Current Store version is higher")
        } else {
            print("Latest New version is higher")
        }

Swift 3 版本：

let currentStoreVersion = "1.1.0.2"
let latestMinimumAppVersionRequired = "1.1.1"
if currentStoreVersion.compare(latestMinimumAppVersionRequired, options: NSString.CompareOptions.numeric) == ComparisonResult.orderedDescending {
print("Current version is higher")
} else {
print("Latest version is higher")
}

Answer 8

这里是swift 4.0+版本比较代码

 let currentVersion = "1.2.0"

 let oldVersion = "1.1.1"

 if currentVersion.compare(oldVersion, options: NSString.CompareOptions.numeric) == ComparisonResult.orderedDescending {
        print("Higher")
    } else {
        print("Lower")
    }

Answer 9

我想我只是分享一个为此而汇集的功能。它一点也不完美。请看一下例子和结果。但是，如果您正在检查自己的版本号（我必须这样做来管理数据库迁移之类的事情），那么这可能会有所帮助。

（当然，删除方法中的日志语句。这些是为了帮助您了解它的全部作用）

测试：

[self isVersion:@"1.0" higherThan:@"0.1"];
[self isVersion:@"1.0" higherThan:@"0.9.5"];
[self isVersion:@"1.0" higherThan:@"0.9.5.1"];
[self isVersion:@"1.0.1" higherThan:@"1.0"];
[self isVersion:@"1.0.0" higherThan:@"1.0.1"];
[self isVersion:@"1.0.0" higherThan:@"1.0.0"];

// alpha tests
[self isVersion:@"1.0b" higherThan:@"1.0a"];
[self isVersion:@"1.0a" higherThan:@"1.0b"];
[self isVersion:@"1.0a" higherThan:@"1.0a"];
[self isVersion:@"1.0" higherThan:@"1.0RC1"];
[self isVersion:@"1.0.1" higherThan:@"1.0RC1"];

结果：

1.0 > 0.1
1.0 > 0.9.5
1.0 > 0.9.5.1
1.0.1 > 1.0
1.0.0 < 1.0.1
1.0.0 == 1.0.0
1.0b > 1.0a
1.0a < 1.0b
1.0a == 1.0a
1.0 < 1.0RC1       <-- FAILURE
1.0.1 < 1.0RC1     <-- FAILURE

请注意 alpha 有效，但您必须非常小心。一旦你在某个时候进入 alpha，你就不能通过改变它后面的任何其他次要数字来扩展它。

代码：

- (BOOL) isVersion:(NSString *)thisVersionString higherThan:(NSString *)thatVersionString {

// LOWER
if ([thisVersionString compare:thatVersionString options:NSNumericSearch] == NSOrderedAscending) {
    NSLog(@"%@ < %@", thisVersionString, thatVersionString);
    return NO;
}

// EQUAL
if ([thisVersionString compare:thatVersionString options:NSNumericSearch] == NSOrderedSame) {
    NSLog(@"%@ == %@", thisVersionString, thatVersionString);
    return NO;
}

NSLog(@"%@ > %@", thisVersionString, thatVersionString);
// HIGHER
return YES;
}

Answer 10

我的 iOS 库 AppUpdateTracker 包含一个 NSString category 来执行这种比较。 （实现基于DonnaLea's answer。）

用法如下：

[@"1.4" isGreaterThanVersionString:@"1.3"]; // YES
[@"1.4" isLessThanOrEqualToVersionString:@"1.3"]; // NO

此外，您可以使用它来跟踪应用的安装/更新状态：

[AppUpdateTracker registerForAppUpdatesWithBlock:^(NSString *previousVersion, NSString *currentVersion) {
    NSLog(@"app updated from: %@ to: %@", previousVersion, currentVersion);
}];
[AppUpdateTracker registerForFirstInstallWithBlock:^(NSTimeInterval installTimeSinceEpoch, NSUInteger installCount) {
    NSLog(@"first install detected at: %f amount of times app was (re)installed: %lu", installTimeSinceEpoch, (unsigned long)installCount);
}];
[AppUpdateTracker registerForIncrementedUseCountWithBlock:^(NSUInteger useCount) {
    NSLog(@"incremented use count to: %lu", (unsigned long)useCount);
}];

Answer 11

Glibc 有一个函数strverscmp 和versionsort……不幸的是，它不能移植到 iPhone，但你可以很容易地编写自己的函数。这种（未经测试的）重新实现仅来自阅读记录的行为，而不是来自阅读 Glibc 的源代码。

int strverscmp(const char *s1, const char *s2) {
    const char *b1 = s1, *b2 = s2, *e1, *e2;
    long n1, n2;
    size_t z1, z2;
    while (*b1 && *b1 == *b2) b1++, b2++;
    if (!*b1 && !*b2) return 0;
    e1 = b1, e2 = b2;
    while (b1 > s1 && isdigit(b1[-1])) b1--;
    while (b2 > s2 && isdigit(b2[-1])) b2--;
    n1 = strtol(b1, &e1, 10);
    n2 = strtol(b2, &e2, 10);
    if (b1 == e1 || b2 == e2) return strcmp(s1, s2);
    if (n1 < n2) return -1;
    if (n1 > n2) return 1;
    z1 = strspn(b1, "0"), z2 = strspn(b2, "0");
    if (z1 > z2) return -1;
    if (z1 < z2) return 1;
    return 0;
}

Answer 12

如果您知道每个版本号正好有 3 个用点分隔的整数，您可以解析它们（例如使用 sscanf(3)）并比较它们：

const char *version1str = "1.0.1";
const char *version2str = "1.2.5";
int major1, minor1, patch1;
int major2, minor2, patch2;
if(sscanf(version1str, "%d.%d.%d", &major1, &minor1, &patch1) == 3 &&
   sscanf(version2str, "%d.%d.%d", &major2, &minor2, &patch2) == 3)
{
    // Parsing succeeded, now compare the integers
    if(major1 > major2 ||
      (major1 == major2 && (minor1 > minor2 ||
                           (minor1 == minor2 && patch1 > patch2))))
    {
        // version1 > version2
    }
    else if(major1 == major2 && minor1 == minor2 && patch1 == patch2)
    {
        // version1 == version2
    }
    else
    {
        // version1 < version2
    }
}
else
{
    // Handle error, parsing failed
}

Answer 13

要快速检查版本，您可以使用以下方法

switch newVersion.compare(currentversion, options: NSStringCompareOptions.NumericSearch) {
    case .OrderedDescending:
        println("NewVersion available  ")
        // Show Alert Here

    case .OrderedAscending:
        println("NewVersion Not available  ")
    default:
        println("default")
    }

希望对您有所帮助。

Answer 14

这是一个递归函数，可以处理任意长度的多个版本格式。它也适用于@"1.0" 和@"1.0.0"

static inline NSComparisonResult versioncmp(const NSString * a, const NSString * b)
{
    if ([a isEqualToString:@""] && [b isEqualToString:@""]) {
        return NSOrderedSame;
    }

    if ([a isEqualToString:@""]) {
        a = @"0";
    }

    if ([b isEqualToString:@""]) {
        b = @"0";
    }

    NSArray<NSString*> * aComponents = [a componentsSeparatedByString:@"."];
    NSArray<NSString*> * bComponents = [b componentsSeparatedByString:@"."];
    NSComparisonResult r = [aComponents[0] compare:bComponents[0] options:NSNumericSearch];

    if(r != NSOrderedSame) {
        return r;
    } else {
        NSString* newA = (a.length == aComponents[0].length) ? @"" : [a substringFromIndex:aComponents[0].length+1];
        NSString* newB = (b.length == bComponents[0].length) ? @"" : [b substringFromIndex:bComponents[0].length+1];
        return versioncmp(newA, newB);
    }

}

测试样本：

versioncmp(@"11.5", @"8.2.3");
versioncmp(@"1.5", @"8.2.3");
versioncmp(@"1.0", @"1.0.0");
versioncmp(@"11.5.3.4.1.2", @"11.5.3.4.1.2");

Answer 15

基于@nathan-de-vries 的answer，我写了SemanticVersion.swift 用于比较Semantic Version。

特点：

1.21.2.0-alpha1.2.0-beta1.2.01.2.0+build1.2.0.01.2.991.11.0

代码：

public struct SemanticVersion: ExpressibleByStringLiteral, ExpressibleByIntegerLiteral, ExpressibleByFloatLiteral {
    public var stringLiteral: String
    public init(stringLiteral literal: String) {
        stringLiteral = literal
    }
    public init(integerLiteral literal: Int) {
        stringLiteral = String(literal)
    }
    public init(floatLiteral literal: Double) {
        stringLiteral = String(literal)
    }
}

extension SemanticVersion: Comparable {
    private var prepared: String {
        return stringLiteral.replacingOccurrences(of: "-", with: "\0") + "\n"
    }
    public static func < (a: SemanticVersion, b: SemanticVersion) -> Bool {
        return a.prepared.compare(b.prepared, options: .numeric) == .orderedAscending
    }
}

// MARK: EXTENSION

public extension String {
    var semanticVersion: SemanticVersion {
        return SemanticVersion(stringLiteral: self)
    }
}

public extension Int {
    var semanticVersion: SemanticVersion {
        return SemanticVersion(integerLiteral: self)
    }
}

public extension Double {
    var semanticVersion: SemanticVersion {
        return SemanticVersion(floatLiteral: self)
    }
}

用法/测试用例：

XCTAssertTrue(UIDevice.current.systemVersion.semanticVersion >= 14.0)

XCTAssertTrue(2.semanticVersion         < "2.0-a")
XCTAssertTrue("2.0-a".semanticVersion   < "2.0-b")
XCTAssertTrue("2.0-b".semanticVersion   < 2.0)
XCTAssertTrue(2.0.semanticVersion       < "2.0+a")
XCTAssertTrue("2.0+a".semanticVersion   < "2.0+b")
XCTAssertTrue("2.0+b".semanticVersion   < "2.0.0")
XCTAssertTrue("2.0.0".semanticVersion   < 2.1)
XCTAssertTrue(2.1.semanticVersion       < 2.99)
XCTAssertTrue(2.99.semanticVersion      < 11.0)