【发布时间】:2021-12-04 11:58:19
【问题描述】:
我需要从其他九个主题的组合中创建一个 Kafka 主题,所有这些主题都是由 Debezium PostgreSQL 源连接器以 AVRO 格式生成的。首先,我正在尝试(到目前为止没有成功)合并来自两个主题的字段。
所以,首先根据“REQUEST”主题创建一个 ksqlDB 表:
ksql> CREATE TABLE TB_REQUEST (ID STRUCT<REQUEST_ID BIGINT> PRIMARY KEY)
WITH (KAFKA_TOPIC='REQUEST', FORMAT='AVRO');
我觉得一切都很好:
ksql> DESCRIBE TB_REQUEST;
Name : TB_REQUEST
Field | Type
-----------------------------------------------------------------------------------------------------------------------
ID | STRUCT<REQUEST_ID BIGINT> (primary key)
BEFORE | STRUCT<REQUEST_ID BIGINT, REQUESTER_ID INTEGER, STATUS_ID>
AFTER | STRUCT<REQUEST_ID BIGINT, REQUESTER_ID INTEGER, STATUS_ID>
SOURCE | STRUCT<VERSION VARCHAR(STRING), CONNECTOR VARCHAR(STRING), NAME VARCHAR(STRING), TS_MS BIGINT, SNAPSHOT VARCHAR(STRING), DB VARCHAR(STRING), SEQUENCE VARCHAR(STRING), SCHEMA VARCHAR(STRING), TABLE VARCHAR(STRING), TXID BIGINT, LSN BIGINT, XMIN BIGINT>
OP | VARCHAR(STRING)
TS_MS | BIGINT
TRANSACTION | STRUCT<ID VARCHAR(STRING), TOTAL_ORDER BIGINT, DATA_COLLECTION_ORDER BIGINT>
-----------------------------------------------------------------------------------------------------------------------
For runtime statistics and query details run: DESCRIBE <Stream,Table> EXTENDED;
然后我从“EMPLOYEE”主题创建另一个表:
ksql> CREATE TABLE TB_EMPLOYEE (ID STRUCT<EMPLOYEE_ID INT> PRIMARY KEY)
WITH (KAFKA_TOPIC='EMPLOYEE', FORMAT='AVRO');
再次,一切似乎都很好。
ksql> DESCRIBE TB_EMPLOYEE;
Name : TB_EMPLOYEE
Field | Type
-----------------------------------------------------------------------------------------------------------------------
ID | STRUCT<EMPLOYEE_ID INTEGER> (primary key)
BEFORE | STRUCT<EMPLOYEE_ID INTEGER, NAME VARCHAR(STRING), HIRING_DATE DATE>
AFTER | STRUCT<EMPLOYEE_ID INTEGER, NAME VARCHAR(STRING), HIRING_DATE DATE>
SOURCE | STRUCT<VERSION VARCHAR(STRING), CONNECTOR VARCHAR(STRING), NAME VARCHAR(STRING), TS_MS BIGINT, SNAPSHOT VARCHAR(STRING), DB VARCHAR(STRING), SEQUENCE VARCHAR(STRING), SCHEMA VARCHAR(STRING), TABLE VARCHAR(STRING), TXID BIGINT, LSN BIGINT, XMIN BIGINT>
OP | VARCHAR(STRING)
TS_MS | BIGINT
TRANSACTION | STRUCT<ID VARCHAR(STRING), TOTAL_ORDER BIGINT, DATA_COLLECTION_ORDER BIGINT>
-----------------------------------------------------------------------------------------------------------------------
For runtime statistics and query details run: DESCRIBE <Stream,Table> EXTENDED;
但是通过尝试创建我的目标表并按员工 ID 加入以前的表。
ksql> CREATE TABLE REQUEST_EMPLOYEE AS
SELECT RQ.ID->REQUEST_ID, RQ.AFTER->REQUESTER_ID, RQ.AFTER->STATUS_ID, EM.ID->EMPLOYEE_ID, EM.AFTER->NAME AS REQUESTER
FROM TB_REQUEST RQ
JOIN TB_EMPLOYEE EM ON RQ.AFTER->REQUESTER_ID = EM.ID->EMPLOYEE_ID;
我收到以下错误:
Could not determine output schema for query due to error: Invalid join condition: table-table joins require to join on the primary key of the right input table. Got RQ.AFTER->REQUESTER_ID = EM.ID->EMPLOYEE_ID.
Statement: CREATE TABLE REQUEST_EMPLOYEE WITH (KAFKA_TOPIC='REQUEST_EMPLOYEE', PARTITIONS=1, REPLICAS=1) AS SELECT
RQ.ID->REQUEST_ID REQUEST_ID,
RQ.AFTER->REQUESTER_ID REQUESTER_ID,
RQ.AFTER->STATUS_ID STATUS_ID,
EM.ID->EMPLOYEE_ID EMPLOYEE_ID,
EM.AFTER->NAME REQUESTER
FROM TB_REQUEST RQ
INNER JOIN TB_EMPLOYEE EM ON ((RQ.AFTER->REQUESTER_ID = EM.ID->EMPLOYEE_ID))
EMIT CHANGES;
查看“DESCRIBE TB_EMPLOYEE”命令的输出,在我看来“EM.ID->EMPLOYEE_ID”是正确的选择。我错过了什么?
提前致谢。
PS:ksqlDB 0.21.0 版本
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标签: join struct apache-kafka ksqldb debezium