Zend Framework URL 到特定模块中的操作

Question

我有 2 个模块：“Mobilewebapp”和“Backoffice”。我的默认模块是“Mobilewebapp”。 我的后台有一个布局“backoffice.phtml”。在那里我有以下内容：

<a href="<?php echo $this->url(array('controller' => 'user', 'action' => 'logout'), null, true) ?>">Logout</a>

问题是链接总是转到默认模块“mobilewebapp”。我已经尝试过了，但还是一样：

<a href="<?php echo $this->url(array('module' => 'backoffice', 'controller' => 'user', 'action' => 'logout'), null, true) ?>">Logout</a>

我的应用程序.ini：

[制作]
phpSettings.display_startup_errors = 1
phpSettings.display_errors = 1
includePaths.library = APPLICATION_PATH "/../library"
bootstrap.path = APPLICATION_PATH "/Bootstrap.php"
bootstrap.class= "引导"
appnamespace = "应用程序"
resources.frontController.controllerDirectory = APPLICATION_PATH "/controllers"
resources.frontController.params.displayExceptions = 1
resources.layout.layoutPath = APPLICATION_PATH "/layouts/scripts/"

resources.frontController.moduleDirectory = APPLICATION_PATH
"/modules" 资源.modules[] = ""
resources.frontController.params.prefixDefaultModule = "1"
resources.frontController.defaultModule = "mobilewebapp"

[暂存：生产]

[测试：生产] phpSettings.display_startup_errors = 1
phpSettings.display_errors = 1

[开发：生产] phpSettings.display_startup_errors = 1
phpSettings.display_errors = 1
resources.frontController.params.displayExceptions = 1

Answer 1

你试过了吗

url(array('module' => 'backoffice', 'controller' => 'user', 'action' => 'logout')) ?>">注销