运动摇动动作不再快速起作用

Question

您好，我遇到了一些难题，我一直在为我的应用重新设计菜单导航。我设法做到了。但现在我的应用程序的一项功能已决定停止运行。

这个想法是你摇动你的手机，它会随机选择一张图片，与应用程序分开的代码工作正常，就像它在所有以前的版本上所做的那样，我什至在它的当前形式上快速运行它以防万一，它工作得很好。

希望有人能指出我出错的方向。

我的代码如下；

    import Foundation
import UIKit


class cocktailChoice: UIViewController {

    @IBOutlet weak var drinkImage: UIImageView!

    var drinkNamesArray:[String] = ["cocktailList0","cocktailList1","cocktailList2","cocktailList3","cocktailList4","cocktailList5","cocktailList6","cocktailList7","cocktailList8","cocktailList9","cocktailList10","cocktailList11","cocktailList12","cocktailList13","cocktailList14","cocktailList15","cocktailList16","cocktailList17","cocktailList18","cocktailList19","cocktailList20","cocktailList21","cocktailList22","cocktailList23","cocktailList24","cocktailList25","cocktailList26","cocktailList27","cocktailList28","cocktailList29","cocktailList30","cocktailList31"]

    override func viewDidLoad() {
        self.view.addGestureRecognizer(self.revealViewController().panGestureRecognizer())
    }

    override func motionEnded(_ motion: UIEventSubtype, with event: UIEvent?) {

        if motion == .motionShake{

            let firstRandomNumber = Int(arc4random_uniform(32))

            let DrinkString:String = self.drinkNamesArray[firstRandomNumber]

            self.drinkImage.image = UIImage(named: DrinkString)

        }

    }

}

它编译没有错误，IBOutlet 已连接，它没有我可以看到的错误，但摇动动作不想播放。现在变得非常沮丧。

Answer 1

这部分不是if motion == .motionShake{，你可以试试这个：

if(event.subtype == .motionShake) {
        print("Shake event!")
    }