如何使用由变量确定的按钮将 a 链接到第二个视图控制器？

Question

我创建了一个 UIPickerView，其中包含一系列服务。我使用 didSelectRow 在 UIPickerView 下方显示我选择的服务。这一切都很好，而且效果很好。

我希望选择的服务将我带到另一个名为该服务的视图控制器。例如，在 Picker 中选择了咖啡店，“咖啡店”显示在选择器下方，您单击一个按钮将带您进入显示有关咖啡店的给定信息的页面。

@Pbush25 感谢您的快速回复。请您看看我的代码并告诉我哪里出了问题，因为我仍然无法让它工作。

import UIKit

class ViewController: UIViewController, UIPickerViewDelegate {

    @IBOutlet weak var SelectedService: UILabel!
    @IBAction func Find(sender: AnyObject) {

    }

    @IBOutlet weak var ItemLabel: UILabel!

    var services = ["Cafe","Coffee Shops","Bar","Takeaway","Sunday Roast","Shoe Mender","Craft Shops","Electrical"]

    override func viewDidLoad() {
        super.viewDidLoad()
        // Do any additional setup after loading the view, typically from a nib.
    }

    override func didReceiveMemoryWarning() {
        super.didReceiveMemoryWarning()
        // Dispose of any resources that can be recreated.
    }

    func numberOfComponentsInPickerView(pickerView: UIPickerView) -> Int{

        return 1
    }

    func pickerView(pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int{
        return services.count   
    }

    func pickerView(pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String!{
        return services[row]
    }
}

Answer 1

正如@JAL 所说，我相信UIPickerViewDelegate 的方法是didSelectRow 或某种程度的东西，它将为您提供所选行的索引路径。当您按下按钮进入下一个屏幕时，您在 prepareForSegue 方法中所要做的就是获取该行的元素并使用 switch 语句来确定哪个新视图控制器根据什么值激活 segue你收到。

编辑：为清楚起见添加了代码。

//save the picked data to a variable
func pickerView(pickerView: UIPickerView!, didSelectRow row: Int, inComponent component: Int)
{
    selection = "\(pickerViewData[row])"
}

//use this variable to decide which segue to take
func prepareForSegue(sender: UIStoryboardSegue){
    switch selection {
    case: "Coffee Shops" 
        performSegueWithIdentifier("goToCoffeeShops", sender: self)

    case: "Some other selection"
        performSegueWithIdentifier("someOtherSegue", sender: self)
    }
}