Python，在循环中初始化类属性

Question

如何在循环中初始化类实例的属性？下面的例子解释了我想要做什么。想象一个有二十到三十个属性的类。必须有一种有效的方法来设置值。我是否必须在字典中更改我的类属性才能这样做？但这将是一个问题，因为我正在使用 Django 框架来创建带有此示例中的类的表。提前致谢！

class Foo():
    fieldA = float()
    fieldB = float()
    fieldC = float()
    fieldD = float()
    fieldE = float()
    fieldF = float()
    # several more field elements


def main():
    foo_instance = Foo()

    # open here excel file with openpyxl library
    wb = openpyxl.load_workbook(BASE_DIR + file, read_only=True, data_only=True)
    ws = wb['sheet1']


    # I would like to iterate through the instance 
    for i in range(1,20):
        foo.fieldA = float(ws['A{}'.format(i)]) #how to iterate through the attributes from foo instance?

    '''
        This is the inefficient way:
        foo.fieldA = float(ws['A1'])
        foo.fieldB = float(ws['A2'])
        foo.fieldC = float(ws['A3'])
        foo.fieldD = float(ws['A4'])
        foo.fieldE = float(ws['A5'])
        etc.
    '''

if __name__ == "__main__":
    main()

Answer 1

尝试将变量放在一个列表中并遍历它们。

my_list = [fieldA, fieldB] # and so on...

# Set an index
index = 0

# Iterate
for field in my_list:
    field = float(ws['A{}'.format(index)])
    index += 1 # Increment index each time

您甚至可以删除变量名，而只使用 my_list[0]、my_list[1] 等列表索引，但这取决于您的需要。