【发布时间】:2013-06-13 20:32:40
【问题描述】:
我有一个关于 Python 2.7 的问题。 urlopen 函数有时会因为网络状况不佳而无法连接。所以我想在上面加一个定时器,这样当连接超时时,它会关闭之前的连接并尝试重新连接。在我的实现中,它会陷入死循环,一次又一次地“尝试重新连接”......有人可以帮我吗?非常感谢!
def getConnection(urlItem, keywords, address):
urlItem.close()
print "Trying to reconnect..."
findArticles(keywords, address)
def findArticles(keywords, address):
urlItem = urllib.urlopen(address)
t = Timer(20.0, getConnection(urlItem, keywords, address))
t.start()
htmlSource = urlItem.read()
t.cancel()
这是我得到的例外:
File "/usr/lib/python2.7/urllib.py", line 84, in urlopen
return opener.open(url)
File "/usr/lib/python2.7/urllib.py", line 205, in open
return getattr(self, name)(url)
File "/usr/lib/python2.7/urllib.py", line 342, in open_http
h.endheaders(data)
File "/usr/lib/python2.7/httplib.py", line 951, in endheaders
self._send_output(message_body)
File "/usr/lib/python2.7/httplib.py", line 811, in _send_output
self.send(msg)
File "/usr/lib/python2.7/httplib.py", line 773, in send
self.connect()
File "/usr/lib/python2.7/httplib.py", line 754, in connect
self.timeout, self.source_address)
File "/usr/lib/python2.7/socket.py", line 553, in create_connection
for res in getaddrinfo(host, port, 0, SOCK_STREAM):
IOError: [Errno socket error] [Errno -2] Name or service not known
【问题讨论】:
-
当我尝试使用 urllib 拉取网站时,当我无法访问该网站时,我得到一个 IOError。我想当你的连接超时时你会得到同样的结果吗?我刚刚测试它拔下,我得到一个 IOError。你如何调用你的函数?您应该会收到一个会中断脚本执行的错误。你是在 Try/Except 中调用这些函数吗?
-
我得到了这个:IOError: [Errno socket error] [Errno -2] Name or service not known。我没有使用 Try/Except...
-
预期效果是什么。该函数继续循环直到它可以加载页面?还是跳过该页面并尝试下一个?
-
@0xhughes 感谢您的建议!我实现了一个 Try/Except 并且它有效。