获取视图行数的元数据答案

【问题标题】：Metadata of Getting number of rows in Views获取视图行数的元数据
【发布时间】：2019-01-08 13:08:37
【问题描述】：

为什么不能在下面的查询中使用 sys.views 返回视图中的行数，而使用 sys.table 你可以

SELECT t.NAME AS table_name,
       s.name AS owner,
       p.[Rows] as NUM_ROWS,
FROM sys.tables t INNER JOIN   
     sys.indexes i 
     ON t.OBJECT_ID = i.object_id INNER JOIN
     sys.partitions p
     ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id inner join
     sys.schemas s on s.schema_id = t.schema_id
WHERE t.NAME NOT LIKE 'dt%' AND i.OBJECT_ID > 255 AND 
      i.index_id <= 1 /* AND
            s.name in ('Schemaname1','Schemaname2') */
GROUP BY t.NAME, i.object_id, i.index_id, i.name,s.name, p.[Rows]
ORDER BY object_name(i.object_id) ;

【问题讨论】：

视图只是存储代码。除非具体化，否则它们不知道视图中有多少行。
带架构
@jarlh sql dbms
你的意思是 MS SQL Server 吗？
@jarlh 是 MS SQL Server

标签： sql sql-server metadata

【解决方案1】：

这是您遇到的语法问题，在 NUM_ROWS 之后的查询中多了一个逗号？

SELECT t.NAME AS table_name,
       s.name AS owner,
       p.[Rows] as NUM_ROWS /*, remove this comma*/
FROM sys.tables t INNER JOIN   
     sys.indexes i 
     ON t.OBJECT_ID = i.object_id INNER JOIN
     sys.partitions p
     ON i.object_id = p.OBJECT_ID AND i.index_id = p.index_id inner join
     sys.schemas s on s.schema_id = t.schema_id
WHERE t.NAME NOT LIKE 'dt%' AND i.OBJECT_ID > 255 AND 
      i.index_id <= 1 /* AND
            s.name in ('Schemaname1','Schemaname2') */
GROUP BY t.NAME, i.object_id, i.index_id, i.name,s.name, p.[Rows]
ORDER BY object_name(i.object_id) ;

【讨论】：