【发布时间】:2014-08-20 08:11:55
【问题描述】:
C#串口编程有问题
我的目标是将 ByteArray 发送到串行端口,而不是作为 ByteArray。
但我无法从串口获取。我试过了:
string gelen = port.ReadExisting();
int asd = port.ReadByte();
string qwe = port.ReadLine();
谁能告诉我怎么了? 谢谢
我的代码:
using System;
using System.Collections.Generic;
using System.ComponentModel;
using System.Data;
using System.Drawing;
using System.Linq;
using System.Text;
using System.Windows.Forms;
using System.IO.Ports;
namespace serial_port_app
{
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
private void button1_Click(object sender, EventArgs e)
{
int text1, text2,text3,text4,text5, text6;
Int32.TryParse(textBox1.Text, out text1);
byte byteValue1 = Convert.ToByte(text1);
Int32.TryParse(textBox2.Text, out text2);
byte byteValue2 = Convert.ToByte(text2);
Int32.TryParse(textBox3.Text, out text3);
byte byteValue3 = Convert.ToByte(text3);
Int32.TryParse(textBox4.Text, out text4);
byte byteValue4 = Convert.ToByte(text4);
Int32.TryParse(textBox5.Text, out text5);
byte byteValue5 = Convert.ToByte(text5);
Int32.TryParse(textBox6.Text, out text6);
byte byteValue6 = Convert.ToByte(text6);
byte[] byteArray = new byte[6];
byteArray[0]=byteValue1;
byteArray[1]=byteValue2;
byteArray[2]=byteValue3;
byteArray[3]=byteValue4;
byteArray[4]=byteValue5;
byteArray[5]=byteValue6;
SerialPort port = new SerialPort("COM1", 9600, Parity.None, 8, StopBits.One);
port.Open();
port.Write(byteArray,0,6);
>>>>>>>>>>>>> string text = port.ReadExisting();
>>>>>>>>>>>>> int asd = port.ReadByte();
>>>>>>>>>>>>> string qwe = port.ReadLine();
int n=dataGridView1.Rows.Add();
dataGridView1.Rows[n].Cells[1].Value = text;
dataGridView1.Rows[n].Cells[2].Value = asd;
dataGridView1.Rows[n].Cells[3].Value = qwe;
dataGridView1.Rows[n].Cells[4].Value = text4;
dataGridView1.Rows[n].Cells[5].Value = text5;
dataGridView1.Rows[n].Cells[6].Value = text6;
if ((n % 2) == 0)
dataGridView1.Rows[n].DefaultCellStyle.BackColor = Color.LightBlue;
else
dataGridView1.Rows[n].DefaultCellStyle.BackColor = Color.LightGreen;
port.Close();
}
编辑正确答案:
删除:
string text = port.ReadExisting();
int asd = port.ReadByte();
string qwe = port.ReadLine();
并添加:
port.DtrEnable = true;
port.RtsEnable = true;
int bytes = port.BytesToRead;
byte[] buffer = new byte[bytes];
port.Read(buffer, 0, bytes);
【问题讨论】:
-
当你尝试那些你尝试过的东西时发生了什么?
-
您忽略了处理握手信号的需要。将 DtrEnabled 和 RtsEnabled 属性设置为 true。使用 Hyperterminal 或 Putty 等其他程序来获得对电气连接和驱动程序的信心。
-
@HansPassant 谢谢,程序运行正常,您的回答正确。
标签: c# serial-port bytearray