在单独的线程中启动 WPF 窗口

Question

我正在使用以下代码在单独的线程中打开一个窗口

public partial class App : Application
{
    protected override void OnStartup(StartupEventArgs e)
    {
        base.OnStartup(e);
    }

    private void button1_Click(object sender, RoutedEventArgs e)
    {
        Thread newWindowThread = new Thread(new ThreadStart(() =>
        {
            // Create and show the Window
            Config tempWindow = new Config();
            tempWindow.Show();
            // Start the Dispatcher Processing
            System.Windows.Threading.Dispatcher.Run();
        }));

        // Set the apartment state
        newWindowThread.SetApartmentState(ApartmentState.STA);
        // Make the thread a background thread
        newWindowThread.IsBackground = true;
        // Start the thread
    }
}

如果我在方法中使用此代码，它会起作用。但是当我如下使用它时，我得到一个错误：

public partial class App : Application
{
    #region Instance Variables
    private Thread newWindowThread;

    #endregion

    protected override void OnStartup(StartupEventArgs e)
    {
        base.OnStartup(e);
        newWindowThread = new Thread(new ThreadStart(() =>
        {
            // Create and show the Window
            Config tempWindow = new Config();
            tempWindow.Show();
            // Start the Dispatcher Processing
            System.Windows.Threading.Dispatcher.Run();
        }));
    }

    private void button1_Click(object sender, RoutedEventArgs e)
    {
        // Set the apartment state
        newWindowThread.SetApartmentState(ApartmentState.STA);
        // Make the thread a background thread
        newWindowThread.IsBackground = true;
        // Start the thread
    }
}

它会抛出以下错误：

System.Threading.ThreadStateException
The state of the thread was not valid to execute the operation

这是什么原因？

Answer 1

@d.moncada，@JPVenson，@TomTom 对不起大家，尤其是 @d.moncada，你的回答让我意识到我真正的错误，如果运行一次直到我的代码工作。但我真正的问题是我尝试在两个位置按下 button1_Click，实际上我使用了一个计时器，该计时器使用

行调用了一个方法

 private void button1_Click(object sender, RoutedEventArgs e)

现在我的问题的解决方案是Detecting a Thread is already running in C# .net?

Answer 2

我认为问题在于您将ApartmentState 设置在Thread 之后开始运行。

试试：

public partial class App : Application
{
    #region Instance Variables
    private Thread newWindowThread;

    #endregion

    protected override void OnStartup(StartupEventArgs e)
    {
        base.OnStartup(e);
        newWindowThread = new Thread(new Thread(() =>
        {
            // Create and show the Window
            Config tempWindow = new Config();
            tempWindow.Show();
            // Start the Dispatcher Processing
            System.Windows.Threading.Dispatcher.Run();
        }));
        // Set the apartment state
        newWindowThread.SetApartmentState(ApartmentState.STA);
        // Make the thread a background thread
        newWindowThread.IsBackground = true;
    }

    private void button1_Click(object sender, RoutedEventArgs e)
    {
        // Start the thread
        newWindowThread.Start();
    }
}

Answer 3

你为什么要这么做？ （几乎）没有理由在您的应用程序中运行 2end UI 线程...如果您想要一个非模态新窗口，请实例化您的窗口并调用 show。

为什么差不多？因为这是一个非常复杂的话题，除非你有很大的预算来开发这种行为，否则你可以没有它。