如果屏幕上的颜色等于某种颜色，Java

Question

我的程序的一部分需要查看屏幕上某个点的颜色是否等于某个颜色，然后执行一个动作。我不知道如何不断检查屏幕上的点以查看颜色是否发生变化。任何帮助将不胜感激！

static Color coal1 = new Color(19, 19, 18); //color i want to match up    

int xRock = gameSquare.x + x_scale; // points on the screen
int yRock = gameSquare.y + y_scale;

java.awt.Color c = robot.getPixelColor(xRock, yRock);//finds the rgb color of the point

if (!c.equals(coal1)){ //this is the part where I am stuck!

}

我希望它继续循环，直到 c 不再等于 coal1。提前致谢！

编辑：新问题是我无法通过 c 发送以检查它是否 = 到 coal1。

新代码（主体）

package Restart;

import java.awt.AWTException;
import java.awt.Color;
import java.awt.Rectangle;
import java.awt.Robot;
import java.awt.event.InputEvent;
import java.awt.image.BufferedImage;
import java.awt.image.DataBuffer;
import java.awt.image.DataBufferInt;
import java.awt.image.WritableRaster;
import java.util.Timer;

public class MineCoal {

    public static Rectangle gameSquare;
    public static boolean runningMine = true;
    static Timer timer = new Timer("Printer");
    static MyTask t = new MyTask();

    public static void main(String[] args) throws InterruptedException {

        lookCoal();

    }

    public static void lookCoal() throws InterruptedException{

        Thread.sleep(2000);
        try {
            Robot robot = new Robot();

            while(runningMine == true){

                gameSquare = new Rectangle(287,139,551,356); //== game square
                BufferedImage img = robot.createScreenCapture(gameSquare);
                WritableRaster r = img.getRaster();
                DataBuffer db = r.getDataBuffer();
                DataBufferInt dbi = (DataBufferInt)db;
                int[] data = dbi.getData();                 

                for (int x_scale = 0; x_scale < gameSquare.width; x_scale += 1) {
                    for(int y_scale = 0; y_scale < gameSquare.height; y_scale += 1) {
                        int rgb = data[x_scale + gameSquare.width * y_scale];

                        if ( (rgb == -15658737)||(rgb ==-15527150) ){ //finds coal
                            //checkinv();
                            if (runningMine == true){

                                runningMine = false;

                                int xRock = gameSquare.x + x_scale; // sets the x and y of the point
                                int yRock = gameSquare.y + y_scale;
                                robot.mouseMove(xRock, yRock);
                                java.awt.Color c = robot.getPixelColor(xRock, yRock); // gets the color of the point
                                System.out.println(c);

                                Thread.sleep(500);
                                robot.mousePress(InputEvent.BUTTON1_MASK);
                                robot.mouseRelease(InputEvent.BUTTON1_MASK);
                                Thread.sleep(1000);
                                System.out.println("Found Rock");

                                timer.schedule(t, 0, 2000); //this goes to check if the point has changed colors but I can not send c through

                            }

                        }

                    }
                }
            }
        }
        catch(AWTException e) {
            e.printStackTrace();
        }

    }

}

定时器类

package Restart;
import java.awt.Color;
import java.util.TimerTask;

class MyTask extends TimerTask {
    //times member represent calling times.
    private int times = 0;
    static Color coal1 = new Color(19, 19, 18);


    public void run() {

        if (coal1.equals(c)) {  //I can not get the c from the other class to compair with coal1
            System.out.println("color is the same");
        } 
        else {
            System.out.println("color changed");

            //Stop Timer.
            this.cancel();
        }
    }
}

Answer 1

java.util.Timer 的 schedule(TimerTask, long, long) 方法可能适合这项工作。

关于您更新的帖子：
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java.awt.Color c = robot.getPixelColor(xRock, yRock); // gets the color of the point

在 TimerTask 的 run() 方法中。由于它需要变量robot、xRock 和yRock，因此您必须将它们作为参数传递给自定义构造函数。
例如：

/* In 'lookCoal(); method */
  // timer.schedule(t, 0 2000)   // <-- replace that with this:
  timer.schedule(new MyTask(robot, xRock, yRock), 0, 2000);

/* In 'MyTask' Class */
  // Add the required variables:
  Robot robot;
  int xRock, yRock;

  // Add a constructor like this:
  MyTask(Robot r, int x, int y) {
      this.robot = r;
      this.xRock = x;
      this.yRock = y;
  }

  // Modify the run method, like this:
  public void run() {
      java.awt.Color c = this.robot.getPixelColor(this.xRock, this.yRock);
      ...

Answer 2

一种方法是使用 javascript。这篇文章可以帮助你如何做到这一点https://stackoverflow.com/a/11506531/1083581

一旦您能够获得所需的 rgb 值，您就可以使用 ajax 请求或 javascript 提交，以便在服务器上进行进一步处理。
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