【发布时间】:2022-01-15 02:32:57
【问题描述】:
我正在使用 Telerik 的 ASP.NET RadAsyncpload 将文件上传到 DB,这与普通的 fileUpload 非常相似。
我的问题是,当使用变量存储数据时,它保存为“null”。在替代方案中,我尝试使用 Server.MapPath,这是为了保存文件夹位置而不是文件。
我做错了什么?
//partial class declarations
(...)
string Ficheiro = string.Empty;
string FileTipo = string.Empty;
byte[] fileBytes = null;
//Save method, triggered by save button after upload
public void SaveFile(object sender, EventArgs e)
{
ListagemTimesheet model = new ListagemTimesheet();
model.IDRecursoHumano = Convert.ToInt32(rdpInvestigadorE.Text);
model.IDEstadoTimesheet = Convert.ToInt32(rcbEstado.SelectedValue);
model.Observações = Obervaçoestxt.Text;
model.AssinaturaTimesheet = txtAssinaturaTimesheet.Text;
model.DataEnvio = DataEnvio.SelectedDate.Value;
if (Objecto.ID > 0)
{
model.ID = Convert.ToInt32(FileID.Text);
if (!string.IsNullOrEmpty(Ficheiro) && FileTipo != null)
{
model.FileName = Path.GetFileNameWithoutExtension(Ficheiro); //FileName
model.FileTipo = Path.GetExtension(FileTipo); //FileExtension
model.FileContent = fileBytes; //Content null
model.FileContent = Encoding.ASCII.GetBytes(HttpContext.Current.Server.MapPath("~/TargetFiles/ + model.FileName")); //Content saved is location of the folder
//Upload method
public void RadAsyncUpload1_FileUploaded(object sender, FileUploadedEventArgs e)
{
RadAsyncUpload1.Visible = false;
Stream fileStream = e.File.InputStream;
Ficheiro = e.File.FileName; // sintaxe metodo
FileTipo = e.File.ContentType;
e.IsValid = true;
byte[] fileBytes = new byte[fileStream.Length - 1 + 1];
fileStream.Read(dados, 0, System.Convert.ToInt32(fileStream.Length));
fileStream.Close();
}
【问题讨论】:
标签: c# file-upload telerik