在 Python 中使用 Scapy 进行数据包计数

Question

我正在使用以下方式从特定 IP 地址捕获 ICMP 数据包：

import scapy.all from *

sniff(filter="icmp and src host 192.168.100.3 and dst host 192.168.100.2", prn=lambda x: x.sprintf("%IP.proto% packets from %IP.src% to %IP.dst%"))

我得到以下输出：

icmp packets from 192.168.100.3 to 192.168.100.2
icmp packets from 192.168.100.3 to 192.168.100.2
icmp packets from 192.168.100.3 to 192.168.100.2
icmp packets from 192.168.100.3 to 192.168.100.2
icmp packets from 192.168.100.3 to 192.168.100.2
...

但是，我只想显示捕获的数据包总数 实时，即

Total icmp packets from 192.168.100.3 to 192.168.100.2 is <total_packets>

上面的这行也应该定期更新，即我只希望在我的输出中始终使用这行。请指导。

Answer 1

首先，你需要修改这一行：

sniff(filter="icmp and src host 192.168.100.3 and dst host 192.168.100.2", prn=lambda x: x.sprintf("%IP.proto% packets from %IP.src% to %IP.dst%"))

lambda x: x.sprintf("%IP.proto% packets from %IP.src% to %IP.dst%" 函数针对每个请求运行

比如：

import os
counter = 0
def dealwithpackets(x):
    global counter
    os.system("cls")
    ips = x.sprintf("Total icmp packets from %IP.src% to %IP.dst%")
    counter += 1
    print(ips + "is" + str(counter))
    
sniff(filter="icmp and src host 192.168.100.3 and dst host 192.168.100.2", prn=lambda x: dealwithpackets(x))

在 Windows 上使用 os.system("cls")，在 Linux 和 macOS 上使用 os.system("clear")