试图获得每个销售渠道的 TOP 10 产品答案

【问题标题】：Trying to get TOP 10 products per sales channel试图获得每个销售渠道的 TOP 10 产品
【发布时间】：2014-12-30 07:35:17
【问题描述】：

我已经找到了一些答案，但在这里没有任何帮助。我需要一个查询来查找一个月内每个销售渠道（总共 5 个）的前 10 种产品。我用一个可怕的 union all 查询试试运气，但我没有得到我需要的结果。（我认为我写的查询不是最好的，反正......）

SELECT a.SKU, a.ProductName, b.SalesChannel, sum(a.PurchasedQuantity) as pq
FROM all_all_orders_items a
INNER JOIN all_all_orders b ON b.AmazonOrderID = a.AmazonOrderID
WHERE b.SalesChannel = 1 AND b.PurchaseDate  BETWEEN NOW() - INTERVAL 30 DAY AND NOW()
GROUP BY a.SKU, b.SalesChannel
UNION ALL
SELECT a.SKU, a.ProductName, b.SalesChannel, sum(a.PurchasedQuantity) as pq
FROM all_all_orders_items a
INNER JOIN all_all_orders b ON b.AmazonOrderID = a.AmazonOrderID
WHERE b.SalesChannel = 2 AND b.PurchaseDate  BETWEEN NOW() - INTERVAL 30 DAY AND NOW()
GROUP BY a.SKU, b.SalesChannel
UNION ALL
SELECT a.SKU, a.ProductName, b.SalesChannel, sum(a.PurchasedQuantity) as pq
FROM all_all_orders_items a
INNER JOIN all_all_orders b ON b.AmazonOrderID = a.AmazonOrderID
WHERE b.SalesChannel = 3 AND b.PurchaseDate  BETWEEN NOW() - INTERVAL 30 DAY AND NOW()
GROUP BY a.SKU, b.SalesChannel
UNION ALL
SELECT a.SKU, a.ProductName, b.SalesChannel, sum(a.PurchasedQuantity) as pq
FROM all_all_orders_items a
INNER JOIN all_all_orders b ON b.AmazonOrderID = a.AmazonOrderID
WHERE b.SalesChannel = 4 AND b.PurchaseDate  BETWEEN NOW() - INTERVAL 30 DAY AND NOW()
GROUP BY a.SKU, b.SalesChannel
UNION ALL
SELECT a.SKU, a.ProductName, b.SalesChannel, sum(a.PurchasedQuantity) as pq
FROM all_all_orders_items a
INNER JOIN all_all_orders b ON b.AmazonOrderID = a.AmazonOrderID
WHERE b.SalesChannel = 5 AND b.PurchaseDate  BETWEEN NOW() - INTERVAL 30 DAY AND NOW()
GROUP BY a.SKU  , b.SalesChannel
ORDER BY pq DESC LIMIT 10

在不查询 db 5 次的情况下获得结果的最佳方法是什么？

现在我只得到整体上最好的产品——但不是特定的销售渠道......

【问题讨论】：

标签： mysql sql select group-by greatest-n-per-group

【解决方案1】：

试试这个：

SELECT A.SKU, A.ProductName, A.SalesChannel, A.pq
FROM (SELECT A.SKU, A.ProductName, A.SalesChannel, A.pq, 
             IF(@SalesChannel = @SalesChannel:=A.SalesChannel, @RowId:=@RowId + 1, @RowId:=1) AS RowNum
      FROM (SELECT a.SKU, a.ProductName, b.SalesChannel, SUM(a.PurchasedQuantity) as pq
            FROM all_all_orders_items a
            INNER JOIN all_all_orders b ON b.AmazonOrderID = a.AmazonOrderID
            WHERE b.SalesChannel IN (1, 2, 3, 4, 5) AND b.PurchaseDate  BETWEEN NOW() - INTERVAL 30 DAY AND NOW()
            GROUP BY a.SKU, b.SalesChannel
            ORDER BY b.SalesChannel, pq DESC
          ) AS A, (SELECT @SalesChannel:=0, @RowId:=1) AS B
      ORDER BY A.SalesChannel, A.pq DESC
     ) AS A 
WHERE A.RowNum <= 10
ORDER BY A.SalesChannel, A.RowNum;

【讨论】：

嗨@Saharsh Shah ..不错的答案。如果你不介意我有一个问题要问你。你是怎么知道表结构的？仅来自 PO 的给定查询？
我也没有得到这种情况。 @SalesChannel = @SalesChannel:=A.SalesChannel你能帮我理解一下吗？

【解决方案2】：

也许这种查询可能有用：

SELECT 
   b.SalesChannel, a.SKU, a.ProductName, b.SalesChannel, sum(a.PurchasedQuantity) as pq
FROM 
   all_all_orders_items a
   INNER JOIN all_all_orders b ON b.AmazonOrderID = a.AmazonOrderID
WHERE 
   b.SalesChannel IN (1, 2, 3, 4, 5) AND b.PurchaseDate  BETWEEN NOW() - INTERVAL 30 DAY AND NOW()
GROUP BY 
   b.SalesChannel, a.SKU, b.SalesChannel
ORDER BY
   b.SalesChannel ASC, pq DESC LIMIT 50

希望对你有帮助

【讨论】：