将 PostgreSQL 转换为 MySQL

Question

我正在学习有关如何在银行对帐单数据集中查找重复交易的教程。我拥有所需的所有数据，但在让查询与 MySQL 一起使用时遇到问题。关于如何将其转换为 MySQL 的任何想法？

WITH transactions_with_date_diff AS (
SELECT  
    ROW_NUMBER() OVER(PARTITION BY description ORDER BY accounting_date),
    accounting_date - LAG(accounting_date) OVER(PARTITION BY description ORDER BY accounting_date) AS date_diff,
    LAST_VALUE(amount) OVER(PARTITION BY description ORDER BY accounting_date) AS latest_amount,
    *
FROM transactions
)

SELECT
description,
COUNT(*) AS transactions_count,
MIN(accounting_date) AS subscription_started,
MAX(accounting_date) AS latest_transaction,
SUM(amount) AS total_amount
FROM transactions_with_date_diff
WHERE
date_diff IS NOT NULL
AND date_diff BETWEEN 25 AND 35
GROUP BY 1
HAVING COUNT(*) > 1
ORDER BY 2 DESC

错误是：

Query 1 ERROR: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '*
    FROM transactions
    )

    SELECT
    description,
    COUNT(*) AS trans' at line 6

更新

我根据反馈调整了 SQL 查询，并提供了示例数据。现在我收到一条不同的错误消息。

查询：

WITH transactions_with_date_diff AS (
    SELECT
        *,
        ROW_NUMBER() OVER(PARTITION BY description ORDER BY accounting_date),
        accounting_date - LAG(accounting_date) OVER(PARTITION BY description ORDER BY accounting_date) AS date_diff,
        LAST_VALUE(amount) OVER(PARTITION BY description ORDER BY accounting_date) AS latest_amount
    FROM transactions
)

SELECT
    description,
    COUNT(*) AS transactions_count,
    MIN(accounting_date) AS subscription_started,
    MAX(accounting_date) AS latest_transaction,
    SUM(amount) AS total_amount
FROM transactions_with_date_diff
WHERE
    date_diff IS NOT NULL
    AND date_diff BETWEEN 25 AND 35
GROUP BY 1
HAVING COUNT(*) > 1
ORDER BY 2 DESC;

返回以下错误：

Query 1 ERROR: Can't group on 'transactions_count'

示例表数据：

id	accounting_date	description	amount
1	2020-12-31	APPLE.COM/BILL	-24.03
2	2021-01-05	ALIEXPRESS.COM ALIEXPRESS	-33
3	2021-01-11	MICROSOFT*XBOX	-399.60

Answer 1

这个查询应该在 MySQL 和 Postgres 中运行：

WITH transactions_with_date_diff AS (
      SELECT t.*,
            ( t.accounting_date - LAG(t.accounting_date) OVER (PARTITION BY t.description ORDER BY t.accounting_date) ) AS date_diff,
            LAST_VALUE(t.amount) OVER (PARTITION BY t.description ORDER BY t.accounting_date) AS latest_amount
      FROM transactions t
     )
SELECT tdd.description,
       COUNT(*) AS transactions_count,
       MIN(tdd.accounting_date) AS subscription_started,
       MAX(tdd.accounting_date) AS latest_transaction,
       SUM(tdd.amount) AS total_amount
FROM transactions_with_date_diff tdd
WHERE tdd.date_diff BETWEEN 25 AND 35
GROUP BY tdd.description
HAVING COUNT(*) > 1
ORDER BY transactions_count DESC;

事实上，这是标准 SQL，应该可以在几乎任何数据库中运行（假设支持该功能。请注意更改：

• CTE 中没有未命名的列。我刚刚删除了ROW_NUMBER()。
• 所有表引用都有别名
• GROUP BY 和 ORDER BY 子句不使用位置符号。
• NOT NULL 比较是多余的。 BETWEEN 不会为 NULL 值返回 TRUE。

Answer 2

我认为您的 AS 倒退了，您当前正在尝试将表分配给名称，而不是将名称分配给表。

试试这个：

WITH (
SELECT  
    ROW_NUMBER() OVER(PARTITION BY description ORDER BY accounting_date),
    accounting_date - LAG(accounting_date) OVER(PARTITION BY description ORDER BY accounting_date) AS date_diff,
    LAST_VALUE(amount) OVER(PARTITION BY description ORDER BY accounting_date) AS latest_amount,
    *
FROM transactions
) AS transactions_with_date_diff