针对单个条件按多列分组

Question

我在下面有一个查询正在运行，但不是我想要的。

该查询为我们的 CSR 提取电话数据，我们目前正在获取 15 个代理的数据。当前查询获得了我需要的总数，但将它们全部加起来并给了我一行总数。我想让它显示每个 CSR 的总数。这样做的问题是源表中的每个呼叫记录都有其 4 位数的扩展名作为主叫号码或被叫号码。但是，每条记录中都没有一个字段可以将该用户的分机与呼叫联系起来。它必须作为主叫号码或被叫号码存在。

所以我相信我的逻辑是正确的，除了现在我需要按分机对呼叫进行分组。因此，对于 15 个 CSR，我希望语句返回 15 行，每行都有自己的总计。但由于没有通用字段可供分组，我想我需要按两个字段进行分组。

换句话说，说“如果callingpartyno 有7200，finally calledpartyno 有7200，则将它们分组为分机7200 的总数”。

以下是数据在源表中的外观示例：

    callingpartyno | finallycalledpartyno 
    -------------------------------------
    1234                outside   
    1234                outside   
    1234                outside   
    outsidecall         1234          
    outsidecall         1234          
    outsidecall         1234          
    9876                outside   
    9876                outside   
    9876                outside   
    outsidecall         9876         
    outsidecall         9876                  
    outsidecall         9876                  

如您所见，没有任何东西将每条记录标识为同一个 CSR。

这里是查询：

 SELECT

        sum(Duration) AS total_talk_time_seconds
      , round(sum(Duration) / 60,2) AS total_talk_time_minutes
      , sum(if(LEGTYPE1 = 1,1,0)) AS total_outbound
      , sum(if(LEGTYPE1 = 2,1,0) and ANSWERED = 1) AS total_inbound
      , sum(if(LEGTYPE1 = 2,1,0) and ANSWERED = 0) AS total_missed
      , SUM(IF(LEGTYPE1 = 1, 1, 0)) +                   -- outbound calls
        SUM(IF(LEGTYPE1 = 2, 1, 0))  AS total_calls
      , NOW() AS time_of_report
      , curdate() AS date_of_report
FROM cdrdb.session a
    INNER JOIN cdrdb.callsummary b
      ON a.NOTABLECALLID = b.NOTABLECALLID
    where date(b.ts) = '2017-10-16 00:00:00'
    AND callingpartyno IN (7276,7314, 7295, 7306,7357,7200,7218,7247 7331,7255,7330,7000,7215, 7240,7358,7312) 
    OR  finallycalledpartyno IN (7276,7314, 7295, 7306,7357,7200,7218,7247 7331,7255,7330,7000,7215, 7240,7358,7312) 

因此，查询再次用于提取指定日期的记录，其中任何扩展名都在 callpartyno 或 finally calledpartyno 中，但我需要一种方法将其按这两个分组并将每条记录视为 4 位数扩展名，几乎就像一个用户 ID。

Answer 1

这正是group by 子句的用途。通过插入case 语句，我们可以使用您自己的条件创建一个ID。

 select
  case 
    when callingpartyno       in (7276,7314,7295,7306,7357,7200,7218,7247,7331,7255,7330,7000,7215,7240,7358,7312)
      then callingpartyno
    when finallycalledpartyno in (7276,7314,7295,7306,7357,7200,7218,7247,7331,7255,7330,7000,7215,7240,7358,7312)
      then finallycalledpartyno
  end as id
  , sum(duration) as total_talk_time_seconds
  , round(sum(duration) / 60,2) as total_talk_time_minutes
  , sum(if(legtype1 = 1,1,0)) as total_outbound
  , sum(if(legtype1 = 2,1,0) and answered = 1) as total_inbound
  , sum(if(legtype1 = 2,1,0) and answered = 0) as total_missed
  , sum(if(legtype1 = 1, 1, 0)) +                   -- outbound calls
    sum(if(legtype1 = 2, 1, 0))  as total_calls
  , now() as time_of_report
  , curdate() as date_of_report
from 
  cdrdb.session a
  join cdrdb.callsummary b
    on a.notablecallid = b.notablecallid
where 
  date(b.ts) = '2017-10-16 00:00:00'
  and (
    callingpartyno           in (7276,7314,7295,7306,7357,7200,7218,7247,7331,7255,7330,7000,7215,7240,7358,7312)
    or  finallycalledpartyno in (7276,7314,7295,7306,7357,7200,7218,7247,7331,7255,7330,7000,7215,7240,7358,7312)
  )
group by
  id -- <-- the calculated field we created in the select clause

我还更正了您的 or 声明。像您一样在括号外使用它会使日期或多或少无关紧要。

Answer 2

我建议：

SELECT sum(Duration) AS total_talk_time_seconds,
       round(sum(Duration) / 60, 2) AS total_talk_time_minutes,
       sum(LEGTYPE1 = 1) AS total_outbound,
       sum(LEGTYPE1 = 2 and ANSWERED = 1) AS total_inbound,
       sum(LEGTYPE1 = 2 and ANSWERED = 0) AS total_missed,
       SUM(LEGTYPE1 in (1, 2)) AS total_calls,
       NOW() AS time_of_report,
       curdate() AS date_of_report
FROM cdrdb.session s INNER JOIN
     cdrdb.callsummary cs
      ON s.NOTABLECALLID = cs.NOTABLECALLID
where date(b.ts) = '2017-10-16' and
      (callingpartyno IN (7276, 7314, 7295, 7306, 7357, 7200,7218,7247, 7331, 7255, 7330, 7000, 7215, 7240,7358,7312)  or
       finallycalledpartyno IN (7276,7314, 7295, 7306,7357,7200, 7218,7247, 7331, 7255, 7330, 7000, 7215, 7240, 7358, 7312) 
      )
group by (case when callingpartyno IN (7276, 7314, 7295, 7306,7357, 7200, 7218, 7247, 7331,7255,7330,7000,7215, 7240,7358,7312)
               then callingpartyno else finallycalledpartyno
          end);

您真正的问题是 where 子句中的逻辑括号。

另外，我做了以下改动：

• 删除了if()。如果要使用 MySQL 扩展，只需使用将布尔值视为整数的扩展即可。
• 使用in 而不是链式比较
• 无需在字符串文字中包含日期的时间部分。