OrientDB：仅遍历具有某些属性的边

Question

我想从一个顶点开始遍历，只沿着匹配特定表达式的边（例如：friendsWith.type="bestFriend"）。我该怎么做呢？

此外，我必须对一堆顶点运行此操作。是否可以通过遍历的“头”来组织事物？理想的回报是：

[[start1, [list of all the vertices during traversal], [start2, [...]],...]

Answer 1

我用这张图试过

我使用这个带有参数rid的javascript函数

var g=orient.getGraph();
var nodes = [];
var previous=[];
var currently=[];
var b=g.command("sql","select from " + rid);
if(b.length>0){
    var vertex=b[0];
    previous.push(vertex);
    nodes.push(vertex);
    do{
        for(i=0;i<previous.length;i++){
            var vertexOut=previous[i];
            var edges=g.command("sql","select expand(outE('friendsWith')) from "+ vertexOut.getId());
            for(s=0;s<edges.length;s++){ 
                var edge=edges[s];
                var type= edge.getProperty("type");
                if(type=="bestFriend"){
                    var vertices=g.command("sql","select expand(inV('friendsWith')) from "+ edge.getId());
                    var vertex=vertices[0];
                    var found=false;          
                    for(k=0;k<nodes.length;k++){
                        var id=nodes[i].getId();
                        var id_v=vertex.getId()
                        if(id==id_v){
                            found=true;
                            break;
                        }
                    }
                    if(found==false){
                        currently.push(vertex);
                        nodes.push(vertex);
                    }
                }
            }
        }
        change();
    }while(previous.length>0);
    return nodes;
}

function change(){
    previous=[];
    for (indice=0;indice<currently.length;indice++)
        previous.push(currently[indice]);
    currently=[];
}

和select expand(node) from (select myFunction("#9:0") as node) 我得到了

希望对你有帮助。

Answer 2

试试这个：

select outV().name as start, inV().name as end from(traverse * from friendsWith while type = "bestFriend")

不用遍历也可以。

希望对你有帮助。

问候。