【发布时间】:2012-02-28 09:26:59
【问题描述】:
您好,我有一个这样的程序:
CREATE PROCEDURE dbo.DWS_PROG (
@fromDate datetime = '2012-01-01',
@maxMoney money = 200,
@limit int = 200
)
AS
SET NOCOUNT ON;
SELECT TOP (@limit)
convert(int,P.P_ID) AS 'ID'
, max(convert(MONEY,isnull(P.NGp,P.NGz))) AS 'NG'
, max(convert(MONEY,(CASE WHEN D.Doc_Type = 0x0000000000000016
THEN Cash_PLN
ELSE 0 END))) AS 'Interests'
, (SELECT TOP 1 convert(VARCHAR, H.Data_zmiany,105)
FROM dbo.Pozew_Historia_Stanow H
WHERE H.P_ID = P.P_ID
AND H.Stan_nastepny_id = 0x000000000000000D /*PZ*/) AS 'Data Pozwu'
, max((CASE WHEN Sad_Id=0x0000000000000E08
THEN 'EL'
ELSE 'PA' END)) AS 'TYPE'
, max((CASE WHEN Cost_Name =0x0000000000000008
THEN convert(varchar, Pay_Date,105)
ELSE NULL END)) AS 'Data pierwszego kosztu wpisu sądowego'
, (SELECT TOP 1 convert(VARCHAR, H.Data_zmiany,105)
FROM dbo.Pozew_Historia_Stanow H
WHERE H.P_ID = P.P_ID
AND H.Stan_nastepny_id = 0x00000000000000DD /*EGZ-1*/) AS 'Data wszczęcia egzekucji'
, sum((CASE WHEN D.Doc_Type = 0x0000000000000003
AND D.Pay_Date >= @fromDate
AND D.Pay_Date < DATEADD(mm,DATEDIFF(mm,0,@fromDate) + 1,0)
THEN Cash_PLN
ELSE 0 END)) AS 'M0'
FROM dbo.Pozew P
JOIN dbo.Orders Z
ON Z.Orders_Id = P.Orders_Id
JOIN dbo.Docs D
ON D.P_ID = P.P_ID
WHERE ((P.NGp IS NOT NULL AND P.NGp < @maxMoney) OR (P.NGp IS NULL AND P.NGz < @maxMoney))
AND P.Stan IN ('PZ-PORAŻKA','PZ-PORAŻ-UB','PZ-PSPPOR-SP','PZ-PSPPOR-UP','PZ-PSSSUK-UP','PZ-ZAPŁATA','EGZ-C-ROSZ-1','EGZ-C-ROSZ-2','EGZ-SUKCES-S','EGZ-ZAS-R','EGZ-NZAS-R','EGZ-BS-1C','EGZ-WSZP-1','EGZ-WSZP-2','EGZ-SPL')
AND (SELECT TOP 1 dbo.Docs.Pay_Date
FROM dbo.Docs
WHERE dbo.Docs.P_ID = P.P_ID
AND dbo.Docs.Cost_Name = 0x0000000000000008
ORDER BY dbo.Docs.Pay_Date) >= @fromDate
GROUP BY P.P_ID
这基本上可以正常工作,但我有一个错误。 在 JOIN 之前的最后一行中,我为所有类型为 0x00...03 且 Pay_date 介于 @param 和 param 的月末之间的文档汇总现金。简单有效:)
但我必须用子查询替换@fromDate:
SELECT TOP 1 dbo.Docs.Pay_Date
FROM dbo.Docs
WHERE dbo.Docs.P_ID = P.P_ID
AND dbo.Docs.Cost_Name = 0x0000000000000008
AND dbo.Docs.Pay_Date >= @fromDate
ORDER BY dbo.Docs.Pay_Date
因此,对于每个文档查询,都将采用特定付款类型的第一个日期,然后将从该日期开始到月底的所有付款相加。
SUM 应如下所示:
SUM((CASE WHEN D.Doc_Type = 0x0000000000000003
AND D.Pay_Date >=
(SELECT TOP 1 dbo.Docs.Pay_Date
FROM dbo.Docs
WHERE dbo.Docs.P_ID = P.P_ID
AND dbo.Docs.Cost_Name = 0x0000000000000008
AND dbo.Docs.Pay_Date >= @fromDate
ORDER BY dbo.Docs.Pay_Date)
AND D.Pay_Date < DATEADD(mm, DATEDIFF(mm, 0,
(SELECT TOP 1 dbo.Docs.Pay_Date
FROM dbo.Docs
WHERE dbo.Docs.P_ID = P.P_ID
AND dbo.Docs.Cost_Name = 0x0000000000000008
AND dbo.Docs.Pay_Date >= @fromDate
ORDER BY dbo.Docs.Pay_Date)) + 1,0)
THEN Cash_PLN
ELSE 0 END)) AS 'M0'
但在这样做之后,Management Studio 会引发错误:
无法对包含聚合或子查询的表达式执行聚合函数。
我试图解决这个问题将近 2 天。 有什么想法吗?
抱歉没有显示表的结构,但是数据库太大了,我只需要一个方法来解决这个错误:)
我的表格如下所示: 表 Pozew:id、name 等
表文档:docid、p_id(来自 Pozew 表的键)、doc_type、cost_name、pay_date、cash_PLN
示例记录如下所示:
文档:
1,1,15,8,'2011-02-04',400
1,1, 3,5,'2011-02-09',0
1,1, 3,5,'2011-02-12',0
1,1, 3,5,'2011-02-04',0
简单场景: 我们在 docs 表中添加一条记录,说明我们有第 1 个文档,cost_name=0x8,然后添加其他文档,但 Doc_Type = 0x3。
因此,我们希望获取所有 doc_Type =0x3 并且在 cost_name=0x8 的第一个文档的创建日期和月末之间添加的所有文档。 但是我们必须为每个 Pozew_id 对它们进行分组。
对不起,我的英语倒了:/
我创建了一个简单的查询,可以更清楚地显示我的问题:
DECLARE @fromDate varchar
SET @fromDate = '2011-06-01'
SELECT TOP 100
sum((CASE WHEN D.Typ_dokumentu = 0x0000000000000003
AND D.Data_platnosci >=
(SELECT TOP 1 Data_platnosci
FROM Dokumenty
WHERE Pozew_Id = P.Pozew_Id
AND Nazwa_kosztu = 0x0000000000000008
AND Data_platnosci >= @fromDate
GROUP BY Pozew_Id)
AND Data_platnosci < DATEADD(mm,DATEDIFF(mm,0,
(SELECT TOP 1 Data_platnosci
FROM Dokumenty
WHERE Pozew_Id = P.Pozew_Id
AND Nazwa_kosztu = 0x0000000000000008
AND Data_platnosci >= @fromDate
GROUP BY Pozew_Id)
) + 1,0) THEN Kwota_PLN ELSE 0 END)) AS 'M0'
FROM
Dokumenty D
JOIN Pozew P
ON D.Pozew_Id = P.Pozew_Id
WHERE
((P.NGp IS NOT NULL
AND
P.NGp < 200)
OR
(P.NGp IS NULL
AND
P.NGz < 200))
AND
P.Stan IN ('PZ-PORAŻKA','PZ-PORAŻ-UB','PZ-PSPPOR-SP')
AND
(SELECT TOP 1
dbo.Dokumenty.Data_platnosci
FROM
dbo.Dokumenty
WHERE
dbo.Dokumenty.Pozew_Id = P.Pozew_Id
AND
dbo.Dokumenty.Nazwa_kosztu = 0x0000000000000008
ORDER BY
dbo.Dokumenty.Data_platnosci) >= @fromDate
【问题讨论】:
-
抱歉@Filip De Vos 格式混乱:/
-
不用担心。在 vim 中的 gg=G 上。
标签: sql-server tsql aggregate-functions