语法错误 SQL Join 语句答案

【问题标题】：Syntax Error SQL Join Statement语法错误 SQL Join 语句
【发布时间】：2013-10-17 13:59:27
【问题描述】：

我有想要加入的表格。它们通过客户匹配编号和客户匹配编号相关联。我想从一个表中输入数据，然后与另一个表连接，然后显示第二个表的结果。我的代码如下所示：

SELECT [title], 
       [customer_no], 
       [forename], 
       [surname], 
       [res_addr_1], 
       [res_addr_2], 
       [city],   
       [country], 
       [res_postcode], 
       [DOB], 
       [Home_phone_no], 
       [Mobile_phone_no] 
 FROM Customer
 LEFT JOIN Account ON cust_match_no 
      FROM Customer = customer_match_no 
      FROM Account  
 WHERE Account.account_no = '12345678';

但是，我在“=”附近不断收到错误语法错误，我不知道为什么！

【问题讨论】：

标签： sql sql-server

【解决方案1】：

这不是 FROM 子句的用途。 FROM 指定查询中的“主”表。为了在 JOIN 中指定哪些表应该匹配的字段，如果有任何歧义，您需要使用表的名称或别名来限定这些字段，就像您在 WHERE 子句中所做的那样：WHERE Account.account_no = ...。在您的情况下，这似乎是不必要的，因为来自 Account 的字段被命名为 cust_match_no 而另一个是 customer_match_no，但无论如何您都可以这样改写您的查询：

SELECT 
    [title], 
    [customer_no], 
    [forename], 
    [surname], 
    [res_addr_1], 
    [res_addr_2], 
    [city], 
    [country], 
    [res_postcode], 
    [DOB], 
    [Home_phone_no], 
    [Mobile_phone_no] 
FROM Customer cus
LEFT JOIN Account acc ON cus.cust_match_no = acc.customer_match_no
WHERE acc.account_no = '12345678';

同样的建议也适用于 SELECT 子句中列名不明确的情况。假设客户和帐户表中都有一个“国家”字段。然后，您应该限定这些列以消除歧义：

SELECT
    [Customer].[Country],
    [Account].[Country]
    ....

PS。请原谅我的英语

【讨论】：

【解决方案2】：

SELECT [title], [customer_no], [forename], [surname],
[res_addr_1], [res_addr_2], [city], [country], [res_postcode], 
[DOB], [Home_phone_no], [Mobile_phone_no] FROM Customer
LEFT JOIN Account ON 
cust_match_no = customer_no WHERE Account.account_no = '12345678';

【讨论】：

【解决方案3】：

         SELECT [title], [customer_no], [forename], [surname], [res_addr_1], [res_addr_2], 
[city],   [country], [res_postcode], [DOB], [Home_phone_no], [Mobile_phone_no] FROM Customer
LEFT JOIN Account ON Account.cust_match_no = Customer.customer_match_no 
WHERE Account.account_no = '12345678';

【讨论】：

【解决方案4】：

试试这样：

SELECT [title], 
   [customer_no], 
   [forename], 
   [surname], 
   [res_addr_1], 
   [res_addr_2], 
   [city],   
   [country], 
   [res_postcode], 
   [DOB], 
   [Home_phone_no], 
   [Mobile_phone_no] 
FROM Customer
LEFT JOIN Account ON cust_match_no = customer_match_no    
WHERE Account.account_no = '12345678';

【讨论】：

【解决方案5】：

试试这样：

SELECT 
    [title],
    [customer_no], 
    [forename], 
    [surname], 
    [res_addr_1], 
    [res_addr_2], 
    [city], 
    [country], 
    [res_postcode], 
    [DOB], 
    [Home_phone_no], 
    [Mobile_phone_no] 
FROM 
    Customer 
LEFT JOIN 
    Account 
ON 
    cust_match_no = customer_match_no 
WHERE 
    Account.account_no = '12345678'

【讨论】：