您可以尝试将“通用”核苷酸定义为它所代表的一组字母,然后将您的序列转换为此类集合的列表,并扫描一个序列是否存在与另一个序列兼容的位置。
这可能不是最有效的代码,但似乎可以工作(请仔细检查我的循环索引是否正确......)。
A = {"A"}
C = {"C"}
G = {"G"}
T = {"T"}
R = A | G
Y = C | T
S = G | C
W = A | T
K = G | T
M = A | C
B = C | G | T
D = A | G | T
H = A | C | T
V = A | C | G
N = {"A", "C", "G", "T"}
letter2nucl = {
"A" : A,
"C" : C,
"G" : G,
"T" : T,
"R" : R,
"Y" : Y,
"S" : S,
"W" : W,
"K" : K,
"M" : M,
"B" : B,
"D" : D,
"H" : H,
"V" : V,
"N" : N}
def is_subseq(seq1, seq2):
l1 = len(seq1)
l2 = len(seq2)
nucls1 = [letter2nucl[letter] for letter in seq1]
nucls2 = [letter2nucl[letter] for letter in seq2]
i = 0
while i < 1 + l2 - l1:
subseq = True
for j, nucl in enumerate(nucls1):
if not (nucls2[i+j] & nucl):
# empty set intersection
subseq = False
break
if subseq:
return True
i += 1
return False
seq1 = "ACC"
seq2 = "CGMBHTW"
if is_subseq(seq1, seq2):
print("%s is subsequence of %s" % (seq1, seq2))
seq1 = "GRT"
seq2 = "AATCBAT"
if is_subseq(seq1, seq2):
print("%s is subsequence of %s" % (seq1, seq2))
结果是:
ACC is subsequence of CGMBHTW
GRT is subsequence of AATCBAT
然后,您可以在使用 Biopython 的 SeqIO 函数读取的序列上使用它。