range, if then, 根据数据打印输出的语句答案

【问题标题】：range, if then, statement to print output based on datarange, if then, 根据数据打印输出的语句
【发布时间】：2021-02-08 02:55:49
【问题描述】：

我想让该值根据指定范围内的值的输出返回响应。

import requests
import json
import time
url = 'https://api.gdax.com/products/BTC-USD/trades'
res = requests.get(url)
json_res = json.loads(res.text)


print('val ', json_res[0]['price'])

buy = range(32000, 36000)
sell = range(39000, 50000)

if json_res in buy:
    print('Low')

elif json_res in sell:
    print('Too High')

这是我正在寻找的输出示例

val 38000.00002545
Too High

【问题讨论】：

标签： python python-3.x string if-statement range

【解决方案1】：

阅读注释行

import requests
import json
import time
url = 'https://api.gdax.com/products/BTC-USD/trades'
res = requests.get(url)
json_res = json.loads(res.text)
price = int(float(json_res[0]['price']) // 1) # Convert from str to float to int (to match the range value)

print('val ', price)

buy = range(32000, 39000) # I changed the max range to 39000 as the current BTC price is 38xxx
sell = range(39000, 50000)

if price in buy:
    print('Low')

elif price in sell:
    print('Too High')

优点：

我仍然使用你的range 语法
我警告你当前的 BTC 价格

【讨论】：

【解决方案2】：

import requests
import json
import time
url = 'https://api.gdax.com/products/BTC-USD/trades'
res = requests.get(url)
json_res = json.loads(res.text)


print('val ', json_res[0]['price'])

if 32000 < float(val)  < 3600:
    print('Low')
elif  39000 < float(val) < 50000:
     print('Too High')

【讨论】：

【解决方案3】：

import requests
import json
import time
url = 'https://api.gdax.com/products/BTC-USD/trades'
res = requests.get(url)
json_res = json.loads(res.text)


print('val ', json_res[0]['price'])

buy = range(32000, 36000)
sell = range(39000, 50000)

if float(json_res[0]['price']) in buy:
    print('Low')

elif float(json_res[0]['price']) in sell:
    print('Too High')
    
else:
    if  float(json_res[0]['price']) <32000:
        print('Lower Than low')
    
    elif float(json_res[0]['price']) >50000:
        print('Higher Than high')
        
    else:
        print('In Between')

【讨论】：