Python 脚本中未达到 elif 语句

Question

在下面的代码中，if 语句到达并运行良好。然而，elif 声明似乎没有任何效果。当脚本运行时，当满足elif 语句的条件时，什么也没有发生，当我按两次返回按钮时，脚本只是继续跳过elif 语句。

我的代码：

            print("If you want to name this window press 1, if you want to describe it press 2")
            if input() == "1":
                print("Please enter this window's title:")
                current_window_title = input()
                print("Do you also want to describe this window? P.S: You can do this later.)")
                if input().lower() == "yes":
                    print("Please enter this window's description:")
                    current_window_description = input()
                else:
                    current_window_description = "None"
            elif input() == "2":
                print("Please enter this window's description:")
                current_window_description = input()
                print("Do you also want to give this window a title? P.S: You can do this later.")
                if input().lower() == "yes":
                    print("Please enter this window's title:")
                    current_window_title = input()

Answer 1

代码中有太多不想要的input() 语句，导致它突然工作。

另外，由于python的input()函数也有打印的能力，你可以将print()和input()组合成一个语句。

所有修改如下：

Input = input("If you want to name this window press 1, if you want to describe it press 2")

if Input == "1":
    current_window_title = input("Please enter this window's title:")

    if input("Do you also want to describe this window? P.S: You can do this later.)").lower() == "yes":
        current_window_description = input("Please enter this window's description:")
    else:
        current_window_description = "None"
        

elif Input == "2":
    current_window_description = input("Please enter this window's description:")
    if input("Do you also want to give this window a title? P.S: You can do this later.").lower() == "yes":
        current_window_title = input("Please enter this window's title:")

Answer 2

你必须在 if 之前使用输入变量 elif else 阻塞。

answer=input("If you want to name this window press 1, if you want to describe it press 2:")
            if answer == "1":
               Code section 1
           elif answer=="2":
               Code section 2
           else : 
              print ("wrong command")

Answer 3

如果你想达到 2，你的代码会要求输入两次。第一次，它会要求输入，它在 if 语句中，你会输入 2，它不会匹配。第二次它会要求输入，你在 elif 语句中，它会工作。

最好先得到输入的结果，然后再进行评估。

print("If you want to name this window press 1, if you want to describe it press 2")
result = input()
if result == "1":
    print("Please enter this window's title:")
    current_window_title = input()
    print("Do you also want to describe this window? P.S: You can do this later.)")
    if input().lower() == "yes":
        print("Please enter this window's description:")
        current_window_description = input()
    else:
        current_window_description = "None"
elif result == "2":
    print("Please enter this window's description:")
    current_window_description = input()
    print("Do you also want to give this window a title? P.S: You can do this later.")
    if input().lower() == "yes":
        print("Please enter this window's title:")
        current_window_title = input()

Answer 4

您需要将用户输入的初始 input() 移到 if 和 elif 语句之外，以便它们与相同的值进行比较。目前，elif 永远不会捕获“2”的输入，除非您输入第二个输入（再次输入“2”）。试试这样的。

print("If you want to name this window press 1, if you want to describe it press 2")
user_input = input()
if user_input == "1":
    print("Please enter this window's title:")
    current_window_title = input()
    print("Do you also want to describe this window? P.S: You can do this later.)")
    if input().lower() == "yes":
        print("Please enter this window's description:")
        current_window_description = input()
    else:
        current_window_description = "None"
elif user_input == "2":
    print("Please enter this window's description:")
    current_window_description = input()
    print("Do you also want to give this window a title? P.S: You can do this later.")
    if input().lower() == "yes":
        print("Please enter this window's title:")
        current_window_title = input()

Answer 5

因为你从用户那里得到了一个输入并且在相同的范围内，如果这个输入量在 elif 中不可用，你可以做这两件事，它会正常工作：

print("If you want to name this window press 1, if you want to describe it press 2")
inp = input()
if inp == "1":
    print("Please enter this window's title:")
    current_window_title = input()
    print("Do you also want to describe this window? P.S: You can do this later.)")
    if input().lower() == "yes":
        print("Please enter this window's description:")
        current_window_description = input()
    else:
        current_window_description = "None"
elif inp == "2":
    print("Please enter this window's description:")
    current_window_description = input()
    print("Do you also want to give this window a title? P.S: You can do this later.")
    if input().lower() == "yes":
        print("Please enter this window's title:")
        current_window_title = input()

或：

print("If you want to name this window press 1, if you want to describe it press 2")
if input() == "1":
    print("Please enter this window's title:")
    current_window_title = input()
    print("Do you also want to describe this window? P.S: You can do this later.)")
    if input().lower() == "yes":
        print("Please enter this window's description:")
        current_window_description = input()
    else:
        current_window_description = "None"
if input() == "2":
    print("Please enter this window's description:")
    current_window_description = input()
    print("Do you also want to give this window a title? P.S: You can do this later.")
    if input().lower() == "yes":
        print("Please enter this window's title:")
        current_window_title = input()