【问题标题】:Code is wont output what i input, and wont calculate the input numbers [duplicate]代码不会输出输入的内容,也不会计算输入数字[重复]
【发布时间】:2014-10-17 21:28:44
【问题描述】:

所以这是一个计算器问题。我们将有一个 Calculator 类(包含其他三个类)、Number 类(用于对要处理的数量进行类型检查)、Operation 类(用于五个操作)和 Memory 类(用于存储函数)) .

当我输入数字时,它不会输出数字,也不会计算输入的数字。抱歉,如果有任何混淆。任何帮助将不胜感激。

import java.util.*;

public class calculatortest{
private Num num;
private Ope ope;

public static void main(String args[]){
       calculatortest c = new calculatortest();
       c.start();
}

public calculatortest()
{

}
public void start()
{
    describeProgram();
    getInput();
    displayOutput();
    //getMemory();
}
private void describeProgram()
{
    System.out.println("this is kc program and it starts from here");

}
private void displayOutput()
{
    System.out.println("Input number 1: " + num.number1());
    System.out.println("Input operator: " + ope.operator());
    System.out.println("Input number 2: " + num.number2());
    System.out.println("Answer is: " + ope.answer());
}
private void getInput()
{
    double number11;
    String operator2;
    double number22;

    Scanner scanner = new Scanner(System.in);
    System.out.print("Number 1: ");
    number11 = scanner.nextDouble();
    System.out.print("Operator: ");
    operator2 = scanner.next();
    System.out.print("Number 2: ");
    number22 = scanner.nextDouble();

    //operation = new Operation(number11,operator2, number33);
    num = new Num (number11, number22);
    ope = new Ope (number11, number22);
}   

}
class Num{

private double number11;
private double number22;

public Num (double number11, double number22)
{

}
public double number1()
{
    return number11;
}
public double number2()
{
    return number22;
}
}
class Ope
{
String operator2;
double answer;
double num1, num2;

public Ope(double number11, double number22 )
{
    setNumber11(number11);
    setNumber22(number22);
}

public String operator() {
    // TODO Auto-generated method stub
    return ("does not work");
}

/*public String Ope(String operator)
{
    return operator2;
}*/

public void setNumber11(double number11)
{
    num1 = number11;
}
public void setNumber22(double number22)
{
    num2 = number22;

}
public double answer() {

    if(operator2.equals("+"))
    {
        double answer = num1 + num2;
        return answer;
    }
    else if(operator2.equals("-"))
    {
        double answer = num1 - num2;
        return answer;
    }
    else if(operator2.equals("*"))
    {
        double answer = num1 * num2;
        return answer;
    }
    else if(operator2.equals("/"))
    {
        double answer = num1 / num2;
        return answer;
    }
    return 0;
}


}
//class Mem

This is the OUTPUT:
this is kc program and it starts from here

Number 1: 5

Operator: +

Number 2: 5


Exception in thread "main" java.lang.NullPointerException

at Ope.answer(calculatortest.java:106)

at calculatortest.displayOutput(calculatortest.java:33)

at calculatortest.start(calculatortest.java:20)

at calculatortest.main(calculatortest.java:9)


Input number 1: 0.0

Input operator: does not work

Input number 2: 0.0

【问题讨论】:

    标签: java class if-statement public private-methods


    【解决方案1】:

    你应该像这样定义构造函数来接受操作符:

    public Ope(double number11, String operator, double number22 )
    {
        operator2 = operator;
        setNumber11(number11);
        setNumber22(number22);
    }
    

    然后在 getInput 上这样做:

    operation = new Ope(number11, operator2, number33);

    【讨论】:

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