【发布时间】:2015-10-05 19:06:44
【问题描述】:
我正在构建一个 Chrome 扩展程序,我需要组合 2 个单独的 AJAX 调用,以便我有 1 个成功回调。最好的方法是什么?
Auth.prototype.updateContact = function(id, contact_obj) {
var self = this,
contact_str = JSON.stringify(contact_obj);
return new RSVP.Promise(function(resolve, reject) {
self.authorize()
.then(function() {
$.ajax({
type: "PUT",
url: self.url + "contacts/" + id,
contentType: "application/json; charset=utf-8",
data: contact_str,
dataType: "json",
success: function(data) {
resolve(data);
},
error: function(jqXHR, textStatus, errorThrown) {
var msg = "updateContact error: request: " + id + " " +
contact_str + " response: " + jqXHR.responseText +
" e=" + JSON.stringify(errorThrown);
sendErrorBackground(msg);
reject(jqXHR);
}
});
});
});
};
Auth.prototype.updateContactList = function(id, list_obj) {
var self = this,
list_str = JSON.stringify(list_obj);
return new RSVP.Promise(function(resolve, reject) {
self.authorize()
.then(function() {
$.ajax({
type: "POST",
url: self.url + "add_lists",
contentType: "application/json; charset=utf-8",
data: list_str,
dataType: "json",
success: function(data) {
resolve(data);
},
error: function(jqXHR, textStatus, errorThrown) {
var msg = "updateContactList error: request: " + id + " " +
list_str + " response: " + jqXHR.responseText +
" e=" + JSON.stringify(errorThrown);
sendErrorBackground(msg);
reject(jqXHR);
}
});
});
});
};
尝试使用@Saar的建议
Auth.prototype.updateContact = function(id, contact_obj, list_obj) {
var self = this,
contact_str = JSON.stringify(contact_obj),
list_str = JSON.stringify(list_obj);
var promiseA = new RSVP.Promise(function(resolve, reject) {
self.authorize().then(function() {
$.ajax({
type: "PUT",
url: self.url + "contacts/" + id,
contentType: "application/json; charset=utf-8",
data: contact_str,
dataType: "json",
success: function(data) {
return data
}
});
});
});
var promiseB = new RSVP.Promise(function(resolve, reject) {
self.authorize().then(function() {
$.ajax({
type: "POST",
url: self.url + "add_lists",
contentType: "application/json; charset=utf-8",
data: list_str,
dataType: "json",
success: function(data) {
return data
}
});
});
});
$.when(promiseA, promiseB).then(function(resultA, resultB) {
console.log(resultB);
});
};
【问题讨论】:
-
你已经在使用 Promise 和 jQuery,只需使用
$.when(promiseA,promiseB).then(function(resultA,resultB){//do something here}); -
我读过关于使用
$.when的信息,但我对 promises 不是很熟悉。我编辑了我的帖子以包含我对您的解决方案的最佳尝试,但控制台只记录承诺对象,有什么想法吗?
标签: javascript jquery ajax google-chrome-extension callback