API 平台在 normalizationContext 和 denormalizationContext 上没有显示名字和姓氏

Question

我是 API 平台的新手，我在 API 平台上的用户实体的 normalizationContext 和 denormalizationContext 存在一些问题。当我将 normalizationContext 和 denormalizationContext 添加到 ApiResources 时，是的，我确实在我的 first_name 和 last_name 变量上方添加了 @Groups({"user:read", "user:write"})。但是当尝试从 api 平台发布数据时，我没有看到我的 first_name 和 last_name 变量选项。

这是我的用户实体

<?php

namespace App\Entity;

use Doctrine\ORM\Mapping as ORM;
use Symfony\Component\Security\Core\User\UserInterface;
use ApiPlatform\Core\Annotation\ApiResource;
use Symfony\Component\Serializer\Annotation\Groups;
use Symfony\Component\Validator\Constraints as Assert;

/**
 * @ORM\Entity(repositoryClass="App\Repository\UserRepository")
 * @ApiResource(
 *     normalizationContext={"groups"={"user:read"}},
 *     denormalizationContext={"groups"={"user:write"}},
 * )
 */
class User implements UserInterface
{
    /**
     * @ORM\Id()
     * @ORM\GeneratedValue()
     * @ORM\Column(type="integer")
     */
    private $id;

    /**
     * @ORM\Column(type="string", length=180, unique=true)
     * @Groups({"user:read", "user:write"})
     * @Assert\NotBlank()
     * @Assert\Email()
     */
    private $email;

    /**
     * @ORM\Column(type="json")
     */
    private $roles = [];

    /**
     * @var string The hashed password
     * @ORM\Column(type="string")
     * @Groups({"user:write"})
     */
    private $password;

    /**
     * @ORM\Column(type="string", length=255)
     * @Groups({"user:read", "user:write"})
     */
    private $first_name;

    /**
     * @ORM\Column(type="string", length=255)
     * @Groups({"user:read", "user:write"})
     */
    private $last_name;

    /**
     * @ORM\Column(type="date")
     * @Groups({"user:read", "user:write"})
     */
    private $dob;

    public function getId(): ?int
    {
        return $this->id;
    }

    public function getEmail(): ?string
    {
        return $this->email;
    }

    public function setEmail(string $email): self
    {
        $this->email = $email;

        return $this;
    }

    /**
     * A visual identifier that represents this user.
     *
     * @see UserInterface
     */
    public function getUsername(): string
    {
        return (string) $this->email;
    }

    /**
     * @see UserInterface
     */
    public function getRoles(): array
    {
        $roles = $this->roles;
        // guarantee every user at least has ROLE_USER
        $roles[] = 'ROLE_USER';

        return array_unique($roles);
    }

    public function setRoles(array $roles): self
    {
        $this->roles = $roles;

        return $this;
    }

    /**
     * @see UserInterface
     */
    public function getPassword(): string
    {
        return (string) $this->password;
    }

    public function setPassword(string $password): self
    {
        $this->password = $password;

        return $this;
    }

    /**
     * @see UserInterface
     */
    public function getSalt()
    {
        // not needed when using the "bcrypt" algorithm in security.yaml
    }

    /**
     * @see UserInterface
     */
    public function eraseCredentials()
    {
        // If you store any temporary, sensitive data on the user, clear it here
        // $this->plainPassword = null;
    }

    public function getFirstName(): ?string
    {
        return $this->first_name;
    }

    public function setFirstName(string $first_name): self
    {
        $this->first_name = $first_name;

        return $this;
    }

    public function getLastName(): ?string
    {
        return $this->last_name;
    }

    public function setLastName(string $last_name): self
    {
        $this->last_name = $last_name;

        return $this;
    }

    public function getDob(): ?\DateTimeInterface
    {
        return $this->dob;
    }

    public function setDob(\DateTimeInterface $dob): self
    {
        $this->dob = $dob;

        return $this;
    }
}

我想为 API 平台的读写组提供 first_name 和 last_name 变量。我该如何解决这个问题？

Answer 1

属性需要使用驼峰式。默认情况下，学说期望驼峰式。 Doctrine 没有将 getFirstName() 识别为 $first_name 的 getter。并且由于该属性被声明为私有 api-platform 无法获取该值。

这应该可行：

    /**
     * @ORM\Column(type="string", length=255)
     * @Groups({"user:read", "user:write"})
     */
    private $firstName;    

    public function getFirstName(): ?string
    {
        return $this->firstName;
    }

或者您可以尝试强制教义使用下划线，如下所示：

doctrine:
    orm:
        naming_strategy: doctrine.orm.naming_strategy.underscore