symfony：autowire 具有 null 功能而不为 null

Question

我尝试为我的 symfony API 制作控制器，但是使用 symfony 的自动装配功能总是返回 null，当我使用函数 $trustedUser->getName() 时代码返回 null

当我使用函数时，代码返回 null：$trustedUser->getName() 在控制器中 getTrustedUserByID()

    $this->logger->info($trustedUser->getName()." ".$trustedUser->getId());
    return new JsonResponse([
        "name" => $trustedUser->getName(),
    ]);

我的控制器如下所示：

<?php

namespace App\Controller;

use App\Entity\Status;
use App\Entity\TrustedUser;
use Symfony\Bundle\FrameworkBundle\Controller\AbstractController;
use Symfony\Component\HttpFoundation\Response;
use Symfony\Component\Routing\Annotation\Route;
use Symfony\Component\HttpFoundation\JsonResponse;
use Psr\Log\LoggerInterface;


class TrustedUserController extends AbstractController
{
    private $logger;

    public function __construct(LoggerInterface $logger)
    {
        $this->logger = $logger;
    }
    /**
     * @Route("/trustedUser/{id}", name="getTrustedUserByID", methods={"GET","HEAD"})
     */
    public function getTrustedUserByID(TrustedUser $trustedUser,$id)
    {
        if (!$trustedUser) {
            throw $this->createNotFoundException(
                'No trustedUsers found for id '.$id
            );
        }
        $this->logger->info($trustedUser->getName()." ".$trustedUser->getId());
        return new JsonResponse([
            "name" => $trustedUser->getName(),
        ]);
    }
}

我的实体是这样的：

<?php

namespace App\Entity;

use App\Repository\TrustedUserRepository;
use Doctrine\ORM\Mapping as ORM;

/**
 * @ORM\Entity(repositoryClass=TrustedUserRepository::class)
 */
class TrustedUser
{
    /**
     * @ORM\Id
     * @ORM\GeneratedValue
     * @ORM\Column(type="integer")
     */
    private $id;

    /**
     * @ORM\Column(type="string", length=255)
     */
    private $civilite;

    /**
     * @ORM\Column(type="string", length=255)
     */
    private $name;

    /**
     * @ORM\Column(type="string", length=255)
     */
    private $lastname;

    /**
     * @ORM\Column(type="integer")
     */
    private $phone;

    /**
     * @ORM\Column(type="string", length=255)
     */
    private $mail;

    /**
     * @ORM\OneToOne(targetEntity=Status::class, inversedBy="trustedUser", cascade={"persist", "remove"})
     * @ORM\JoinColumn(nullable=true)
     */
    private $id_status;

    public function getId(): ?int
    {
        return $this->id;
    }

    public function getCivilite(): ?string
    {
        return $this->civilite;
    }

    public function setCivilite(string $civilite): self
    {
        $this->civilite = $civilite;

        return $this;
    }

    public function getName(): ?string
    {
        return $this->name;
    }

    public function setName(string $name): self
    {
        $this->name = $name;

        return $this;
    }

    public function getLastname(): ?string
    {
        return $this->lastname;
    }

    public function setLastname(string $lastname): self
    {
        $this->lastname = $lastname;

        return $this;
    }

    public function getPhone(): ?int
    {
        return $this->phone;
    }

    public function setPhone(int $phone): self
    {
        $this->phone = $phone;

        return $this;
    }

    public function getMail(): ?string
    {
        return $this->mail;
    }

    public function setMail(string $mail): self
    {
        $this->mail = $mail;

        return $this;
    }

    public function getIdStatus(): ?Status
    {
        return $this->id_status;
    }

    public function setIdStatus(Status $id_status): self
    {
        $this->id_status = $id_status;

        return $this;
    }
}

我的存储库如下所示：

<?php

namespace App\Repository;

use App\Entity\TrustedUser;
use Doctrine\Bundle\DoctrineBundle\Repository\ServiceEntityRepository;
use Doctrine\Persistence\ManagerRegistry;

/**
 * @method TrustedUser|null find($id, $lockMode = null, $lockVersion = null)
 * @method TrustedUser|null findOneBy(array $criteria, array $orderBy = null)
 * @method TrustedUser[]    findAll()
 * @method TrustedUser[]    findBy(array $criteria, array $orderBy = null, $limit = null, $offset = null)
 */
class TrustedUserRepository extends ServiceEntityRepository
{
    public function __construct(ManagerRegistry $registry)
    {
        parent::__construct($registry, TrustedUser::class);
    }

    // /**
    //  * @return TrustedUser[] Returns an array of TrustedUser objects
    //  */
    /*
    public function findByExampleField($value)
    {
        return $this->createQueryBuilder('t')
            ->andWhere('t.exampleField = :val')
            ->setParameter('val', $value)
            ->orderBy('t.id', 'ASC')
            ->setMaxResults(10)
            ->getQuery()
            ->getResult()
        ;
    }
    */

    /*
    public function findOneBySomeField($value): ?TrustedUser
    {
        return $this->createQueryBuilder('t')
            ->andWhere('t.exampleField = :val')
            ->setParameter('val', $value)
            ->getQuery()
            ->getOneOrNullResult()
        ;
    }
    */
}

实体和存储库都是使用 make:entity 生成的

And the database looks like this The results looks like this

Answer 1

在我看来，这不像是自动装配问题 - Doctrine 实体不是自动装配的，而是通过 ParamConverter 加载的。这可以通过提供实体的 ID 将实体注入到控制器方法中。

要使其正常工作，您需要安装包sensio/framework-extra-bundle。此软件包包含转换器。

此外，如果您不需要控制器中的原始 ID，则无需注入它。如果找不到实体，包的转换器将自行抛出异常