【发布时间】:2018-10-26 23:30:07
【问题描述】:
我想在 symfony 4 下实现实时搜索,但我卡住了。 希望对各位朋友有所帮助。
我的控制器
/**
* @Route("/search", name="search")
*/
public function searchAction(Request $request){
$user = new User();
$searchTerm = $request->query->get('search');
$em = $this->getDoctrine()->getManager();
$results = $em->getRepository(User::class)->findOneBy(['email' => $searchTerm]);
//$results = $query->getResult();
$content = $this->renderView('search.html.twig', [
'res' => $results,
'val' => $searchTerm
]);
$response = new JsonResponse();
$response->setData(array('list' => $content));
return $response;
}
我的脚本 ajax 这是我的 ajax 脚本
$.ajax({
type: "GET",
url: "{{ path('search') }}",
dataType: "json",
data: {search: input},
cache: false,
success: function (response) {
$('.example-wrapper').replaceWith(response);
//$('.example-wrapper').load("{{ path('search') }}?search="+ $search.val());
console.log(response);
},
error: function (response) {
console.log(response);
}
});
search.html.twig
<form class="example-wrapper" role="search" method="post" action="{{ path('search') }}">
<div>
<input type="text" class="form-control" name="search" value="{{ val }}">
<button type="submit" class="btn btn-success" name="sub">search</button>
</div>
</form>
<div class="example-wrapper">
{% for result in res %}
<p style="display:inline-block;width:200px;">{{ result.fullname }}</p>
<p style="display:inline-block;width:100px;">{{ result.username }}</p>
<p style="display:inline-block;width:300px;">{{ result.email }}</p>
<p style="display:inline-block;width:120px;">{{ result.roles[0] }}</p>
{% endfor %}
</div>
搜索页面看起来我看不到表单,除非取消 ajax 脚本
【问题讨论】:
标签: javascript ajax symfony doctrine-orm symfony4