我应该如何为 CBC 代码实现初始化向量？

Question

from cryptography.hazmat.primitives.ciphers import Cipher, algorithms, modes
from cryptography.hazmat.backends import default_backend


key = b'InformationSecurity M.Sc'
message =   b"""yeahcourse snake"""
IV = '000102030405060708090a0b0c0d0e0f'
aesCipher = Cipher(algorithms.AES(key),
                   modes.CBC(),
                   backend=default_backend())
aesEncryptor = aesCipher.encryptor()
aesDecryptor = aesCipher.decryptor()

    
message += b"E" * (-len(message) % 16) # Padding to full blocks of 16 bytes 
ciphertext = aesEncryptor.update(message)

print("plaintext:",message)
print("ciphertext:",ciphertext.hex()) 
decryptedMessage = aesDecryptor.update(ciphertext)
print("recovered:",decryptedMessage)

一直是 ECB 模式，但现在想将其更改为 CBC 模式。当 aes 运行代码时，它会显示以下消息：

TypeError: __init__() missing 1 required positional argument: 'initialization_vector'

Answer 1

看起来一切都在文档中进行了描述：https://cryptography.io/en/latest/hazmat/primitives/symmetric-encryption/

从文档中，它应该是“modes.CBC(IV)”。你错过了那个论点。