如何对重复数据的数组值求和

Question

我有一个数组，其具有一些相同的ID 值，如下所示。

[
    {"ID":"126871","total":"200.00","currency":"USD","name":"John"},
    {"ID":"126872","total":"2000.00","currency":"Euro","name":"John"},
    {"ID":"126872","total":"1000.00","currency":"Euro","name":"John"},
    {"ID":"126872","total":"500.00","currency":"USD","name":"John"},
    {"ID":"126872","total":"1000.00","currency":"Euro","name":"John"},
]

如果ID 值重复，则将相同currency 的总值相加。对于同一个ID的不同currency，不用求和total。

这就是我想要的。

[
    {"ID":"126871","total":"200.00","currency":"USD","name":"John"},
    {"ID":"126872","total":"4000.00","currency":"Euro","name":"John"},
    {"ID":"126872","total":"500.00","currency":"USD","name":"John"}
]

我被上述问题困住了。我已经尽可能地尝试了。但我得到了错误的结果。我非常感谢任何建议。

Answer 1

@Cloud 我已经为您的要求制作了功能，感谢@M。 I. 看看这个总和部分。

$array = array(
    array("ID"  => "126871","total"=>"200.00","currency"=>"USD","name"=>"John"),
    array("ID"  => "126872","total"=>"2000.00","currency"=>"Euro","name"=>"John"),
    array("ID"  => "126872","total"=>"1000.00","currency"=>"Euro","name"=>"John"),
    array("ID"  => "126872","total"=>"500.00","currency"=>"USD","name"=>"John"),
    array("ID"  => "126872","total"=>"1000.00","currency"=>"Euro","name"=>"John"),
);
echo "<pre>";
print_r($array);

function unique_multidim_array($array, $key,$key1,$addedKey) { 
    $temp_array = array(); 
    $i = 0; 
    $key_array = array(); 
    $key1_array = array(); 

    foreach($array as $val) { 
        if (!in_array($val[$key], $key_array) && !in_array($val[$key1], $key1_array)) { 
            $key_array[$i] = $val[$key]; 
            $key1_array[$i] = $val[$key1]; 
            $temp_array[$i] = $val; 
        }else{
            $pkey = array_search($val[$key],$key_array);
            $pkey1 = array_search($val[$key1],$key1_array);
            if($pkey==$pkey1){
                $temp_array[$pkey][$addedKey] += $val[$addedKey];
            }else{
                $key_array[$i] = $val[$key]; 
                $key1_array[$i] = $val[$key1]; 
                $temp_array[$i] = $val; 
            }
            // die;
        }
        $i++; 
    } 
    return $temp_array; 
} 

$nArray = unique_multidim_array($array,"ID","currency","total");
// die;
print_r($nArray);
die;

Answer 2

你需要：

• 使用json_decode将您的json字符串转换为php数组。
• 遍历行并使用复合临时键对它们进行分组。换句话说，从每一行的 ID 和 currency 值生成一个字符串，并将该字符串用作临时唯一键。
• 对分组行的total 值求和。
• 然后通过重新索引行并调用 json_encode() 来准备输出数组以返回 json。

代码：(Demo)

$json='[
    {"ID":"126871","total":"200.00","currency":"USD","name":"John"},
    {"ID":"126872","total":"2000.00","currency":"Euro","name":"John"},
    {"ID":"126872","total":"1000.00","currency":"Euro","name":"John"},
    {"ID":"126872","total":"500.00","currency":"USD","name":"John"},
    {"ID":"126872","total":"1000.00","currency":"Euro","name":"John"}
]';

$array=json_decode($json,true);  // convert to array
foreach($array as $row){
    if(!isset($result[$row['ID'].$row['currency']])){
        $result[$row['ID'].$row['currency']]=$row;  // on first occurrence, store the full row
    }else{
        $result[$row['ID'].$row['currency']]['total']+=$row['total'];  // after first occurrence, add current total to stored total
    }
}
$result=json_encode(array_values($result));  // reindex the array and convert to json
echo $result;  // display

输出：

[
    {"ID":"126871","total":"200.00","currency":"USD","name":"John"},
    {"ID":"126872","total":4000,"currency":"Euro","name":"John"},
    {"ID":"126872","total":"500.00","currency":"USD","name":"John"}
]

Answer 3

内容：创建一个按“ID”和“货币”分组的数组。为重复累积货币。

如何：

• 一次将一行添加到输出数组。
• 如果组不在数组中，则添加它
• 如果它在数组中，则将货币添加到现有记录中。

Demonstration at eval.in

代码：

/** ----------------------------------------------
* Create an output array one row at a time.
* 
* Group by Id and currency.   
* 
* @param array $groups
* 
* @return array
*/
function getCurrencyGroups(array $groups)
{
    $currencyGroups = array();

    foreach ($groups as $item) {

        $id       = $item['ID'];
        $currency = $item['currency'];
        $amount   = $item['total'];

        if (!isset($currencyGroups[$id][$currency])) {
            $currencyGroups[$id][$currency] = $amount;
        }
        else {
            $currencyGroups[$id][$currency] += $amount;
        }
    }

    return $currencyGroups;
}

运行它：

$currencyGroups = getCurrencyGroups($source);

输出：

array (size=2)
  126871 => 
    array (size=1)
      'USD' => string '200.00' (length=6)

  126872 => 
    array (size=2)
      'Euro' => float 4000
      'USD' => string '500.00' (length=6)

Answer 4

我发现自己处于类似的情况，除了我把自己画在一个角落里并且需要使用相同的数组进行输入和输出。我还发现 Manish 的反应有点强硬。

foreach($open_po_report as $pkey => &$po_line){
    foreach($open_po_report as $dkey => $dupe_item){
        //do not compare the exact same line
        if($dupe_item['PoNo'].$dupe_item['Line'] === $po_line['PoNo'].$po_line['Line']){
            continue;
        }
        //once you find a duplicate sum the qty to the original occurance
        if($dupe_item['ItemVendorItem'] === $po_line['ItemVendorItem']){
            $po_line['MyOrder']+=$dupe_item['MyOrder'];
            unset($open_po_report[$dkey]);
        }
        //delete the duplicate entry
    }
}

Answer 5

@Cloud 试试这个。

$array = array(array("ID"   => "126871","total"=>"200.00","currency"=>"USD","name"=>"John",),array("ID" => "126871","total"=>"200.00","currency"=>"USD","name"=>"John",),array("ID" => "126872","total"=>"1000.00","currency"=>"Euro","name"=>"John",));
    echo "<pre>";
    print_r($array);
    $unique = array_map('unserialize', array_unique(array_map('serialize', $array)));

当然@Magnus Eriksson。我正在解释为什么我们在步骤中使用“序列化”和“反序列化”：

第一步：将多维数组转换为一维数组

要将多维数组转换为一维数组，首先要生成数组内部所有元素（包括嵌套数组）的字节流表示。 serialize() 函数可以生成一个值的字节流表示。要生成所有元素的字节流表示，请在 array_map() 函数内调用 serialize() 函数作为回调函数。无论多维数组有多少层，结果都是一维数组。

第 2 步：使值独一无二

要使这个一维数组唯一，请使用array_unique() 函数。

第三步：还原为多维数组

虽然数组现在是唯一的，但值看起来像字节流表示。要将其还原为多维数组，请使用unserialize() 函数。

我现在希望我为什么要编写此代码。