PHP：根据键的值修改关联数组

Question

我有一个这样的数组

Array
(
    [id] => 3
    [type] => default
    [place] => 1
)
Array
(
    [id] => 3
    [type] => default
    [place] => 2
)
Array
(
    [id] => 3
    [type] => default
    [place] => 3
)

这个数组是从这个php创建的

for($count=1;$count <= 3;$count++){
$places_array = array(
    "id" => "3",
    "type" => "default",
    "place" => $count,
);
}

现在我想改变这个数组的结果，如果这个地方被 php mysql 数据找到了。例如我有这个数组。

Array
(
    [id] => 7
    [type] => 1
    [place] => 2
    [description] => This is item place 2
    [image] => this_is_the_image.png
)

如您所见，第二个数组位于“位置 2”。现在我希望结果是这样的

Array
(
    [id] => 3
    [type] => default
    [place] => 1
)
Array
(
    [id] => 7
    [type] => 1
    [place] => 2
    [description] => This is item place 2
    [image] => this_is_the_image.png
)
Array
(
    [id] => 3
    [type] => default
    [place] => 3
)

如何做到这一点？我已经完成了 array_search 函数，但没有运气。 任何人请帮助我

========================编辑完整代码===================== ============ 这是代码，我正在显示数据库中的数据并在while循环函数中调用它

for($count=1;$count <= $max_places;$count++){
    $array[] = array(
        "id" => $res['id'],
        "type" => "default",
        "place" => $count
    );
    while($arr = $stmts->fetch()){
        $key = array_search($arr['place'], array_column($array, 'place'));
        if($key && array_key_exists($key, $array)) {
            $array[$key] = [
                "id" => $arr['id'],
                "type" => $arr['type'],
                "place" => $arr['place'],
                "url" => $arr['url'],
                "image" => $arr['image']
            ];
        }
    }
}

==========================交换码==================== ==========

while($arr = $stmts->fetch()){
        $array[] = [
                "id" => $arr['id'],
                "type" => $arr['type'],
                "place" => $arr['place'],
                "url" => $arr['url'],
                "image" => $arr['image']
        ];
    for($count=1;$count <= $max_places;$count++){
    $key = array_search($arr['place'], array_column($array, 'place'));
    if($key && array_key_exists($key, $array)) {
        $array[] = array(
            "id" => $res['id'],
            "type" => "default",
            "place" => $count
        );
        }
    }  
}

Answer 1

您可以使用内置的 array_multisort() 功能。

从 php.net 复制的示例 一种对多维数组中的键进行排序的好方法，而无需先知道数组中有哪些键：

<?php
    $people = array(
        array("name"=>"Bob","age"=>8,"colour"=>"red"),
        array("name"=>"Greg","age"=>12,"colour"=>"blue"),
        array("name"=>"Andy","age"=>5,"colour"=>"purple")
    );

var_dump($people);

$sortArray = array();

foreach($people as $person){
    foreach($person as $key=>$value){
        if(!isset($sortArray[$key])){
            $sortArray[$key] = array();
        }
        $sortArray[$key][] = $value;
    }
}

$orderby = "name"; //change this to whatever key you want from the array

array_multisort($sortArray[$orderby],SORT_DESC,$people);

var_dump($people);
?>

没有检查您的数组键是否存在，或者您正在搜索的数组数据是否确实存在，但很容易添加。

查看https://www.php.net/manual/de/function.ksort.php（用户贡献）和 https://www.php.net/manual/de/function.array-multisort.php

Answer 2

使用array_column() 和array_search() 获取需要修改的数组key。见以下代码sn -p：

<?php

// Here is trick; get the key of the array using array_column
$key = array_search('2', array_column($array, 'place'));

// If any key found modify the array
if ($key && array_key_exists($key, $array)) {
    $array[$key] = [
        'id' => 7,
        'type' => 1,
        'place' => 2,
        'description' => 'This is item place 2',
        'image' => 'this_is_the_image.png',
    ];
}

print_r($array);

见demo

Answer 3

试试：

for($count=1;$count <= 3;$count++){
    if(array_search($count,array_column("place",$array_from_db)) continue;
    $places_array = array(
        "id" => "3",
        "type" => "default",
        "place" => $count,
        );
}

这将跳过：

Array
(
    [id] => 3
    [type] => default
    [place] => 2
)

===========编辑=============

while($arr = $stmts->fetch())
{
    $array[$arr['place']] = [
        "id" => $arr['id'],
        "type" => $arr['type'],
        "place" => $arr['place'],
        "url" => $arr['url'],
        "image" => $arr['image']
    ];
}
for($count=1;$count <= $max_places;$count++){
    if(!isset($array[$count])){
        $array[$count] = array(
            "id" => $res['id'],
            "type" => "default",
            "place" => $count
        );
    }
}  
ksort($array);

Answer 4

找到答案了，谢谢大家的帮助。

这就是诀窍

首先我们需要像这样确定主数组

for($count=1;$count <= $max_places;$count++){
        $array[$count] = array(
            "id" => $res['id'],
            "type" => "default",
            "place" => $count
        );
} 

然后我们需要找到哪个地方不可用并显示匹配项。

while($arr = $stmts->fetch()){
    $key = array_search($arr['place'], array_column($array, 'place'));
    $key+=1;
    if($key && array_key_exists($key, $array)) {
        $array[$arr['place']] = [
            "id" => $arr['id'],
            "type" => $res['type'],
            "place" => $arr['place'],
            "url" => $arr['url'],
            "image" => $arr['image']
        ];
    }
}

诀窍在于

$key+=1;

因为数组中的默认键是0。 希望这可以帮助其他人