JavaScript 正则表达式匹配数组中的数字

Question

我有以下文字：

 {"status": "ok","data": {"grpd": 0,"obj": 073741824,"objInst": 0,"no": null,"values": [3.523422,0,-323123123,3.423,9223372036854775807,0,"test 123.32",0,0,"",0,0]}}

我需要匹配并在数组“values”中的数字周围加上引号，所以它的结果应该是：

 {"status": "ok","data": {"grpd": 0,"obj": 073741824,"objInst": 0,"no": null,"values": ["3.523422","0","-323123123","3.423","9223372036854775807","0","test 123.32","0","0","","0","0"]}}

数字可以是浮点数、负数和普通数。

Answer 1

您可以循环遍历数据并将其转换为字符串，如下所示：

var data =  {"status": "ok","data": {"grpd": 0,"obj": 073741824,"objInst": 0,"no": null,"values": [3.523422,0,-323123123,3.423,9223372036854775807,0,"test 123.32",0,0,"",0,0]}}

var values = [];

for (var i = 0 ; i < data.data.values.length ; i ++) {
    values.push(String(data.data.values[i]));
}

data.data.values = values;

console.log(data);

Answer 2

您只需有一个循环来检查值是数字还是浮点值并转换为字符串。

var obj1 = {"status": "ok","data": {"grpd": 0,"obj": 073741824,"objInst": 0,"no": null,"values": [3.523422,0,-323123123,3.423,9223372036854775807,0,"test 123.32",0,0,"",0,0]}};

obj1.data.values.forEach(function(value, index, theArray) {
 if (!isNaN(value) || value.toString().indexOf('.') != -1)
    {
       theArray[index] = value.toString();
    }
});

console.log(obj1);

Answer 3

如果你真的需要通过正则表达式来做，那么你可以试试这个。

const regex = /(-?\d+(\.\d+)?)(?![^,]*")/g;
const str = `{"status": "ok","data": {"grpd": 0,"obj": 073741824,"objInst": 0,"no": null,"values": [3.523422,0,-323123123,3.423,9223372036854775807,0,"test 123.32",0,0,"",0,0]}}`;
const subst = `"$1"`;

const result = str.replace(regex, subst);

console.log(result);

Regex Demo

根据评论更新：

(\:\s*|,|\[|\{)\s*(-?\d+(?:\.\d+)?)(?=[,\]\}])

Demo 2

const regex = /(\:\s*|,|\[|\{)\s*(-?\d+(?:\.\d+)?)(?=[,\]\}])/g;
const str = `{"status": "ok","data": {"grpd": 0,"obj": 073741824,"objInst": 0,"no": null,"values": [3.523422,0,-323123123,3.423,"test 123.3,2",0,"test 123.32",0,0,"","adsa22s22",0]}}`;
const subst = `$1"$2"`;


const result = str.replace(regex, subst);

console.log(result);

Answer 4

如果您确实无法更改原始 JSON 以使用字符串表示不在 JS 支持的范围内的数字，那么您可以使用以下内容：

var json = '{"status": "ok","data": {"grpd": 0,"obj": 073741824,"objInst": 0,"no": null,"values": [3.523422,0,-323123123,3.423,9223372036854775807,0,"test 123.32",0,0,"",0,0, "test \\u0022 123", "test \\" 123"]}}';

var inString = false;
var inNumber = false;
var out = '';

for (var index = 0, len = json.length ; index < len ; ++index) {
    var chr = json.charAt(index);
    
    switch (chr) {
        case '"':
            inString = !inString;
            break;
            
        case '\\':
            out += chr + json.charAt(index + 1);
            ++index;
            continue;
            
        case '-':
        case '.':
        case '0':
        case '1':
        case '2':
        case '3':
        case '4':
        case '5':
        case '6':
        case '7':
        case '8':
        case '9':
            if (!inString && !inNumber) {
                out += '"';
                inNumber = true;
            }
            
            break;
            
        default:
            if (inNumber) {
                inNumber = false;
                out += '"';
            }
    }
    
    out += chr;
}

console.log(out);

使用 RegExp 处理字符串中的数字太棘手了，所以我什至没有尝试过。我假设 JSON 是有效的......如果不是，我的粗略解析器将无法很好地处理。我也忽略了数字的7e5 符号，这需要一些额外的工作来避免匹配true 中的e。

我没有明确地针对数组values，但可以对其进行相应调整。具体如何做取决于您是要处理通用 JSON 还是更针对您的确切格式的东西。例如，您可能只在数字达到一定长度时才在数字周围加上引号。通过跟踪数字开始的确切索引而不是仅使用isNumber 标志，这将很容易添加。

如果我要在生产中使用这样的东西，我会编写大量单元测试以确保它确实有效。

Answer 5

let obj = JSON.parse(response);
obj.values = obj.values.map(item => typeof item === 'number' ? '"'+item+'"');
console.log(JSON.stringify(obj));

或使用 es5

obj.values = obj.values.map(function(item) {
  return typeof item === 'number' ? '"'+item+'"';
}

或者代替 typeof item === 'number' 你可以使用 ! isNaN(项目)

Answer 6

先解析成JS对象

var obj = JSON.parse( jsonString );

然后

obj.data.values = obj.data.values.map( function( item ){ return !isNaN( item ) ? String( item ) : item; });

将其转换回 JSON 字符串格式

jsonString  = JSON.stringify( obj );

但是，如果数字超出了 javascript 对象可以接受的范围，则使用此基于正则表达式的解决方案

var str = '{"status": "ok","data": {"grpd": 0,"obj": 073741824,"objInst": 0,"no": null,"values": [3.523422,0,-323123123,3.423,9223372036854775807,0,"test 123.32",0,0,"",0,0]}}';

str = str.replace(/[,|\[](\-){0,1}\d+(\.\d+)*(?=[,|\]])/g, function(match){ var firstChar = match.charAt(0); match = match.substring( 1 ); return firstChar + "\"" + match + "\"" ; });

console.log( str );