在 xslt 1.0 中对嵌套元素进行分组

Question

我一直在研究 XSLT 1.0 中的 Muenchian 分组示例，特别是这个示例 here。但是我无法让它在更复杂的 XML 结构上工作。

我的 XML 当前如下所示：

<?xml version="1.0" encoding="utf-8"?>
<ContestResults>
  <Contests>
    <Contest sportId="35">
      <Sport>Beach Volleyball</Sport>
      <Event>Men's</Event>
      <Ranks>
        <Rank position="1" eventId="1">
          <Athlete>Athlete 1a / Athlete 2a [GER]</Athlete>
          <Result>2</Result>
        </Rank>
        <Rank position="2" eventId="1">
          <Athlete>Athlete 1b / Athlete 2b [NED]</Athlete>
          <Result>0</Result>
        </Rank>
      </Ranks>
    </Contest>
    <Contest sportId="32">
      <Sport>Tennis</Sport>
      <Event>Women's Singles</Event>
      <Ranks>
        <Rank position="1" eventId="2">
          <Athlete>Tennis Athlete 1</Athlete>
          <Result>2</Result>
        </Rank>
        <Rank position="2" eventId="2">
          <Athlete>Tennis Athlete 2</Athlete>
          <Result>1</Result>
        </Rank>
      </Ranks>
    </Contest>
    <Contest sportId="35">
      <Sport>Beach Volleyball</Sport>
      <Event>Men's</Event>
      <Ranks>
        <Rank position="1" eventId="3">
          <Athlete>Athlete 3a / Athlete 4a [AUT]</Athlete>
          <Result>2</Result>
        </Rank>
        <Rank position="2" eventId="3">
          <Athlete>Athlete 3b / Athlete 4b [SUI]</Athlete>
          <Result>0</Result>
        </Rank>
      </Ranks>
    </Contest>
    </Contests>
</ContestResults>

但是，当它们具有相同的 Sport 和 Event 时，我想将 Rank 节点分组到相同的 Ranks 父级下。所以我希望结果看起来像这样：

<?xml version="1.0" encoding="utf-8"?>
<ContestResults>
  <Contests>
    <Contest sportId="35">
      <Sport>Beach Volleyball</Sport>
      <Event>Men's</Event>
      <Ranks>
        <Rank position="1" eventId="1">
          <Athlete>Athlete 1a / Athlete 2a [GER]</Athlete>
          <Result>2</Result>
        </Rank>
        <Rank position="2" eventId="1">
          <Athlete>Athlete 1b / Athlete 2b [NED]</Athlete>
          <Result>0</Result>
        </Rank>
        <Rank position="1" eventId="3">
          <Athlete>Athlete 3a / Athlete 4a [AUT]</Athlete>
          <Result>2</Result>
        </Rank>
        <Rank position="2" eventId="3">
          <Athlete>Athlete 3b / Athlete 4b [SUI]</Athlete>
          <Result>0</Result>
        </Rank>
      </Ranks>
    </Contest>
    <Contest sportId="32">
      <Sport>Tennis</Sport>
      <Event>Women's Singles</Event>
      <Ranks>
        <Rank position="1" eventId="2">
          <Athlete>Tennis Athlete 1</Athlete>
          <Result>2</Result>
        </Rank>
        <Rank position="2" eventId="2">
          <Athlete>Tennis Athlete 2</Athlete>
          <Result>1</Result>
        </Rank>
      </Ranks>
    </Contest>
  </Contests>
</ContestResults>

我只是有点迷失如何做到这一点，因为唯一的其他例子是处理一个更简单的结构，我不确定这是否可能或者我的密钥和模板需要如何构建才能做到这一点。谁能提供一些示例如何实现？

任何建议将不胜感激。

Answer 1

这种转变：

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>
 <xsl:strip-space elements="*"/>

 <xsl:key name="kContestById" match="Contest" use="@sportId"/>

 <xsl:template match="node()|@*">
     <xsl:copy>
       <xsl:apply-templates select="node()|@*"/>
     </xsl:copy>
 </xsl:template>

 <xsl:template match="Contests">
      <Contests>
       <xsl:apply-templates/>
      </Contests>
 </xsl:template>

 <xsl:template match=
  "Contest
    [not(generate-id()
    =
     generate-id(key('kContestById', @sportId)[1]))
     ]"/>
 <xsl:template match="Ranks">
  <Ranks>
    <xsl:apply-templates select="key('kContestById', ../@sportId)/Ranks/Rank"/>
  </Ranks>
 </xsl:template>
</xsl:stylesheet>

应用于提供的 XML 文档时：

<ContestResults>
  <Contests>
    <Contest sportId="35">
      <Sport>Beach Volleyball</Sport>
      <Event>Men's</Event>
      <Ranks>
        <Rank position="1" eventId="1">
          <Athlete>Athlete 1a / Athlete 2a [GER]</Athlete>
          <Result>2</Result>
        </Rank>
        <Rank position="2" eventId="1">
          <Athlete>Athlete 1b / Athlete 2b [NED]</Athlete>
          <Result>0</Result>
        </Rank>
      </Ranks>
    </Contest>
    <Contest sportId="32">
      <Sport>Tennis</Sport>
      <Event>Women's Singles</Event>
      <Ranks>
        <Rank position="1" eventId="2">
          <Athlete>Tennis Athlete 1</Athlete>
          <Result>2</Result>
        </Rank>
        <Rank position="2" eventId="2">
          <Athlete>Tennis Athlete 2</Athlete>
          <Result>1</Result>
        </Rank>
      </Ranks>
    </Contest>
    <Contest sportId="35">
      <Sport>Beach Volleyball</Sport>
      <Event>Men's</Event>
      <Ranks>
        <Rank position="1" eventId="3">
          <Athlete>Athlete 3a / Athlete 4a [AUT]</Athlete>
          <Result>2</Result>
        </Rank>
        <Rank position="2" eventId="3">
          <Athlete>Athlete 3b / Athlete 4b [SUI]</Athlete>
          <Result>0</Result>
        </Rank>
      </Ranks>
    </Contest>
    </Contests>
</ContestResults>

产生想要的正确结果：

<ContestResults>
   <Contests>
      <Contest sportId="35">
         <Sport>Beach Volleyball</Sport>
         <Event>Men's</Event>
         <Ranks>
            <Rank position="1" eventId="1">
               <Athlete>Athlete 1a / Athlete 2a [GER]</Athlete>
               <Result>2</Result>
            </Rank>
            <Rank position="2" eventId="1">
               <Athlete>Athlete 1b / Athlete 2b [NED]</Athlete>
               <Result>0</Result>
            </Rank>
            <Rank position="1" eventId="3">
               <Athlete>Athlete 3a / Athlete 4a [AUT]</Athlete>
               <Result>2</Result>
            </Rank>
            <Rank position="2" eventId="3">
               <Athlete>Athlete 3b / Athlete 4b [SUI]</Athlete>
               <Result>0</Result>
            </Rank>
         </Ranks>
      </Contest>
      <Contest sportId="32">
         <Sport>Tennis</Sport>
         <Event>Women's Singles</Event>
         <Ranks>
            <Rank position="1" eventId="2">
               <Athlete>Tennis Athlete 1</Athlete>
               <Result>2</Result>
            </Rank>
            <Rank position="2" eventId="2">
               <Athlete>Tennis Athlete 2</Athlete>
               <Result>1</Result>
            </Rank>
         </Ranks>
      </Contest>
   </Contests>
</ContestResults>

说明：

正确使用 Muenchian grouping method 并覆盖 identity rule。