像 //*/rating[./@book-id=//book/@id]/@value 这样的 XPath 表达式应该只检索与可用图书 ID 匹配的评级值。
如果您将<rating book-id="3" value="4"/> 添加到 XML 文档,XPath 将只返回第 1 和第 2 本书的值 5 和 3,因为没有 ID 3 的书可用。
使用 VTD 的简单测试方法如下所示:
@Test
public void xpathReference() throws Exception {
byte[] bytes = ("<root>\n"
+ " <book id=\"1\" name=\"Book1\"/>\n"
+ " <book id=\"2\" name=\"Book1\"/>\n"
+ " <rating book-id=\"1\" value=\"5\"/>\n"
+ " <rating book-id=\"2\" value=\"3\"/>\n"
+ " <rating book-id=\"3\" value=\"4\"/>\n"
+ "</root>").getBytes();
VTDGen vtdGenerator = new VTDGen();
vtdGenerator.setDoc(bytes);
vtdGenerator.parse(true);
VTDNav vtdNavigator = vtdGenerator.getNav();
AutoPilot autoPilot = new AutoPilot(vtdNavigator);
autoPilot.selectXPath("//*/rating[./@book-id=//book/@id]/@value");
int id;
int count = 0;
while ((id = autoPilot.evalXPath()) != -1) {
String elementName = vtdNavigator.toString(id);
int text = vtdNavigator.getAttrVal(elementName);
String txt = text != -1 ? vtdNavigator.toNormalizedString(text) : "";
System.out.println("Found match at ID " + id + " in field name '" + elementName + "' with value '" + txt + "'");
count++;
}
System.out.println("Total number of matches: " + count);
assertThat(count, is(equalTo(2)));
}
在执行此测试方法时,您应该会看到与此类似的输出:
Found match at ID 15 in field name 'value' with value '5'
Found match at ID 20 in field name 'value' with value '3'
Total number of matches: 2
根据评论,上面的代码没有以类似迭代的方式提取当前处理的书的数据。下面的代码现在尝试实现这一点:
@Test
public void xpathReference() throws Exception {
byte[] bytes = ("<root>\n"
+ " <book id=\"1\" name=\"Book1\"/>\n"
+ " <book id=\"2\" name=\"Book2\"/>\n"
+ " <book id=\"4\" name=\"Book3\"/>\n"
+ " <rating book-id=\"1\" value=\"5\"/>\n"
+ " <rating book-id=\"2\" value=\"3\"/>\n"
+ " <rating book-id=\"3\" value=\"4\"/>\n"
+ "</root>").getBytes();
VTDGen vtdGenerator = new VTDGen();
vtdGenerator.setDoc(bytes);
vtdGenerator.parse(true);
VTDNav vtdNavigator = vtdGenerator.getNav();
AutoPilot autoPilot = new AutoPilot(vtdNavigator);
autoPilot.selectXPath("//book/@id");
int id;
int count = 0;
while ((id = autoPilot.evalXPath()) != -1) {
String elementName = vtdNavigator.toString(id);
int bookId_id = vtdNavigator.getAttrVal(elementName);
String bookId = bookId_id != -1 ? vtdNavigator.toNormalizedString(bookId_id) : "";
AutoPilot xpathBookName = new AutoPilot(vtdNavigator);
xpathBookName.selectXPath("//book[@id=" + bookId + "]/@name");
String bookName = xpathBookName.evalXPathToString();
AutoPilot xpathRating = new AutoPilot(vtdNavigator);
xpathRating.selectXPath("//rating[@book-id=" + bookId + "]/@value");
String bookRating = xpathRating.evalXPathToString();
if ("".equals(bookRating)) {
System.out.println("Book " + bookName + " with id " + bookId + " has no rating yet");
} else {
System.out.println("Book " + bookName + " with id " + bookId + " has a rating of " + bookRating);
}
count++;
}
System.out.println("Total number of matches: " + count);
assertThat(count, is(equalTo(3)));
}
如果您执行后面的代码,您应该会看到如下输出:
Book Book1 with id 1 has a rating of 5
Book Book2 with id 2 has a rating of 3
Book Book3 with id 4 has no rating yet
Total number of matches: 2
请注意,我确实稍微更新了您第二本书的名称,以便您可以更轻松地看到差异。
...是的,很容易在 Java 代码中获取当前书籍的 id,然后用它构造一个 XPath 表达式,但正如我解释的那样,我希望用户能够使用 XPath 来定义他们的文档格式,所以我不希望代码中有任何特定于格式的东西
VTD 仅支持 XPath 1.0。如果您(或您的客户)能够提出 XPath 1.0 查询,您也应该能够通过 VTD 提取相应的值。我想,普通的 XPath 查询不足以直接提供您需要的内容。
由于示例对于您需要的用例来说可能很简单,因此很难就如何设计您的应用程序来处理此类场景提供任何建议。也许用更详细的例子更新你的问题。处理此问题的一种简单方法是引入必须单独定义的占位符变量,然后在尝试执行此类 XPath 表达式时遇到此类占位符时,只需将这些占位符替换为先前提取值的具体值。