【问题标题】:XSL for Xml: Inserting specific classes using XSLXSL for Xml:使用 XSL 插入特定类
【发布时间】:2012-11-12 23:21:02
【问题描述】:

继上周我提出的问题之后,我还有另一个 XSLT 问题。 XSL for Xml to table transformation for two rows and many columns.

挑战是根据 section 属性为每个插入不同的类。我需要两个不同的输出,如下面的输出所示。我有一个来自上一个问题的示例 XSLT,我想对其进行相应的编辑。

请注意,我正在使用 XSLT 1.0。任何建议或指导将不胜感激。

输入:

<root>
  <page number="1" section="Arsenal">Arsenal</page> 
  <page number="2" section="Arsenal">Arsenal</page> 
  <page number="3" section="Arsenal">Arsenal</page> 
  <page number="4" section="Arsenal">Arsenal</page> 
  <page number="5" section="Arsenal">Arsenal</page> 
  <page number="6" section="Arsenal">Arsenal</page> 
  <page number="7" section="Chelsea">Chelsea</page> 
  <page number="8" section="Chelsea">Chelsea</page> 
  <page number="9" section="Chelsea">Chelsea</page> 
  <page number="10" section="Chelsea">Chelsea</page> 
  <page number="11" section="Chelsea">Chelsea</page> 
  <page number="12" section="Chelsea">Chelsea</page> 
  <page number="13" section="ManUnited">ManUnited</page> 
  <page number="14" section="ManUnited">ManUnited</page> 
  <page number="15" section="ManUnited">ManUnited</page> 
  <page number="16" section="ManUnited">ManUnited</page> 
  <page number="17" section="ManUnited">ManUnited</page> 
  <page number="18" section="ManUnited">ManUnited</page> 
  <page number="19" section="ManCity">ManCity</page> 
  <page number="20" section="ManCity">ManCity</page> 
  <page number="21" section="ManCity">ManCity</page> 
  <page number="22" section="ManCity">ManCity</page> 
  <page number="23" section="ManCity">ManCity</page> 
  <page number="24" section="ManCity">ManCity</page> 
 </root>

输出 1:

<table>
<tr>
<td class="AFC">Arsenal</td>
<td></td>
<td class="CFC">Chelsea</td>
<td></td>
<td class="MUFC">ManUnited</td>
<td></td>
<td class="MCFC">ManCity</td>
<td></td>
</tr>
<tr>
<td>1</td>
<td>6</td>
<td>7</td>
<td>12</td>
<td>13</td>
<td>18</td>
<td>19</td>
<td>24</td>
</tr>
</table>

输出 2:

<table>
<tr>
<td class="Arsenal">Arsenal</td>
<td></td>
<td class="Chelsea">Chelsea</td>
<td></td>
<td class="ManUnited">ManUnited</td>
<td></td>
<td class="ManCity">ManCity</td>
<td></td>
</tr>
<tr>
<td>1</td>
<td>6</td>
<td>7</td>
<td>12</td>
<td>13</td>
<td>18</td>
<td>19</td>
<td>24</td>
</tr>
</table>

@Kirill Polishchuk 提供的当前 XSLT

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" omit-xml-declaration="yes" indent="yes"/>
<xsl:key name="k" match="page" use="@section"/>

<xsl:template match="/root">
<table>
<tr>
<xsl:apply-templates select="page[generate-id() = generate-id(key('k', @section))]"/>
</tr>
<tr>
<xsl:apply-templates select="page[generate-id() = generate-id(key('k', @section))]" mode="page"/>
</tr>
</table>
</xsl:template>

<xsl:template match="page">
<td>
<xsl:value-of select="."/>
</td>
<td></td>
</xsl:template>

<xsl:template match="page" mode="page">
<td>
<xsl:value-of select="@number"/>
</td>
<td>
<xsl:value-of select="key('k', @section)[last()]/@number"/>
</td>
</xsl:template>

</xsl:stylesheet>

【问题讨论】:

    标签: html xml xslt xpath


    【解决方案1】:

    使用这个 XSLT:

    <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:my="my">
      <xsl:output method="xml" omit-xml-declaration="yes" indent="yes"/>
    
      <xsl:key name="k" match="page" use="@section"/>
    
      <xsl:param name="short-name" select="true()"/>
      <!-- Change param to false()-->
    
      <my:data>
        <club name="Arsenal">AFC</club>
        <club name="Chelsea">CFC</club>
        <club name="ManUnited">MUFC</club>
        <club name="ManCity">MCFC</club>
      </my:data>
    
      <xsl:template match="/root">
        <table>
          <tr>
            <xsl:apply-templates select="page[generate-id() = generate-id(key('k', @section))]"/>
          </tr>
          <tr>
            <xsl:apply-templates select="page[generate-id() = generate-id(key('k', @section))]" mode="page"/>
          </tr>
        </table>
      </xsl:template>
    
      <xsl:template match="page">
        <xsl:variable name="class">
          <xsl:choose>
            <xsl:when test="$short-name">
              <xsl:value-of select="document('')/*/*/club[@name = current()/@section]"/>
            </xsl:when>
            <xsl:otherwise>
              <xsl:value-of select="@section"/>
            </xsl:otherwise>
          </xsl:choose>
    
        </xsl:variable>
    
        <td class="{$class}">
          <xsl:value-of select="."/>
        </td>
        <td></td>
      </xsl:template>
    
      <xsl:template match="page" mode="page">
        <td>
          <xsl:value-of select="@number"/>
        </td>
        <td>
          <xsl:value-of select="key('k', @section)[last()]/@number"/>
        </td>
      </xsl:template>
    
    </xsl:stylesheet>
    

    根据参数$short-name,它会呈现您想要的 1st XML 或 2nd

    【讨论】:

    • 再次感谢@Kirill Polishchuk。看起来复杂的要逐行去理解。
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