【发布时间】：2018-05-22 07:52:12
【问题描述】：
我正在使用 SAX Parser 来解析一些 XML 内容。请检查我下面的代码。
public void parse(InputSource is, AppDataBean appDataBean) throws RuntimeException {
int limitCheck;
try {
SAXParserFactory factory = SAXParserFactory.newInstance();
SAXParser saxParser = factory.newSAXParser();
Log.d("SAX",appDataBean.getUrl());
DefaultHandler handler = new DefaultHandler() {
boolean title = false;
boolean link = false;
boolean author = false;
public void startElement(String uri, String localName,
String qName, Attributes attributes)
throws SAXException {
if (qName.equalsIgnoreCase(TITLE)) {
title = true;
}
if (qName.equalsIgnoreCase(LINK)) {
link = true;
}
if (qName.equalsIgnoreCase(AUTHOR)) {
author = true;
}
//Log.d("SAX","Start Element :" + qName);
}
public void endElement(String uri, String localName,
String qName)
throws SAXException {
}
public void characters(char ch[], int start, int length)
throws SAXException {
System.out.println(new String(ch, start, length));
if (title) {
Log.d("SAX","End Element :" + "First Name : "
+ new String(ch, start, length));
title = false;
}
if (link) {
Log.d("SAX","End Element :" + "Last Name : "
+ new String(ch, start, length));
link = false;
}
if (author) {
Log.d("SAX","End Element :" + "Nick Name : "
+ new String(ch, start, length));
author = false;
}
}
};
saxParser.parse(is, handler);
} catch (Exception e) {
e.printStackTrace();
}
}
下面是我的 XML 的样子。
<?xml version="1.0" encoding="UTF-8"?>
<rss xmlns:atom="http://www.w3.org/2005/Atom" version="2.0">
<?xml-stylesheet type="text/xsl" href="rss.xsl"?>
<channel>
<title>MyRSS</title>
<atom:link href="http://www.example.com/rss.php" rel="self" type="application/rss+xml" />
<link>http://www.example.com/rss.php</link>
<description>MyRSS</description>
<language>en-us</language>
<pubDate>Tue, 22 May 2018 13:15:15 +0530</pubDate>
<item>
<title>Title 1</title>
<pubDate>Tue, 22 May 2018 13:14:40 +0530</pubDate>
<link>http://www.example.com/news.php?nid=47610</link>
<guid>http://www.example.com/news.php?nid=47610</guid>
<description>bla bla bla</description>
</item>
</channel>
</rss>
但是在这里，我需要避免使用Channel 标签，并且只读取根标签是Item。那么只有我才能得到真正的内容。我该怎么做？
更新
根据答案的建议，我尝试将 SAX Parser 与 stack 一起使用。下面是代码，但我还是不行，现在它没有为First Name打印任何东西
public void parse(InputSource is, AppDataBean appDataBean) throws RuntimeException {
int limitCheck;
stack = new Stack<>();
try {
SAXParserFactory factory = SAXParserFactory.newInstance();
SAXParser saxParser = factory.newSAXParser();
Log.d("SAX", appDataBean.getUrl());
DefaultHandler handler = new DefaultHandler() {
boolean title = false;
boolean link = false;
boolean author = false;
public void startElement(String uri, String localName,
String qName, Attributes attributes)
throws SAXException {
Log.d("SAX", "localName: " + localName);
if(localName.equalsIgnoreCase("item"))
{
stack = new Stack<>();
stack.push(qName);
}
if (qName.equalsIgnoreCase(TITLE)) {
if(stack.peek().equalsIgnoreCase("item"))
{
title = true;
}
}
if (qName.equalsIgnoreCase(LINK)) {
link = true;
}
if (qName.equalsIgnoreCase(AUTHOR)) {
author = true;
}
//Log.d("SAX","Start Element :" + qName);
}
public void endElement(String uri, String localName,
String qName)
throws SAXException {
stack.pop();
}
public void characters(char ch[], int start, int length)
throws SAXException {
System.out.println(new String(ch, start, length));
if (title) {
Log.d("SAX", "End Element :" + "First Name : "
+ new String(ch, start, length));
title = false;
}
if (link) {
Log.d("SAX", "End Element :" + "Last Name : "
+ new String(ch, start, length));
link = false;
}
if (author) {
Log.d("SAX", "End Element :" + "Nick Name : "
+ new String(ch, start, length));
author = false;
}
}
};
saxParser.parse(is, handler);
} catch (Exception e) {
e.printStackTrace();
}
}
【问题讨论】：
标签： java android xml saxparser