【发布时间】:2020-10-23 01:21:54
【问题描述】:
Teradata 查询:-
select min(elapsed_sec) over (partition by job_name, parent_job_name order by elapsed_sec rows between 1 following and 1 following) - elapsed_sec as diff from xyz
Teradata 查询的输出:-
elapsed_sec row_count row_no diff
0.000 207 143 1.000
1.000 207 144 0.000
1.000 207 145 0.000
1.000 207 146 0.000
1.000 207 147 4,555.000
4,556.000 207 148 1,250.000
5,806.000 207 149 2,038.000
7,844.000 207 150 73.000
注意:- diff 是 current_row 和 next_row 之间的差异
例如。 第一行 1-0=1,第二行 1-1=0 我的 mysql5.6 不支持这个 特征。请帮助获得所需的结果
【问题讨论】:
标签: mysql sql mysql-workbench teradata teradata-sql-assistant